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Nady [450]
3 years ago
8

List all pairs of numbers that would have 20 as their LCM

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0
The pair of numbers that would have 20 as their lcm is 4 and 5
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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
Any suggestions or answers
Bad White [126]

Answer:

3m - 4

Step-by-step explanation:

Divide.

(15mn)/(5n) = 3m

(-20n)/(5n) = -4

3m - 4 is your answer.

~

7 0
3 years ago
At Quality Tees, shirts sell at a
aleksklad [387]
The answer is 6 shirts


12.5x+8=83
12.5x=83-8
12.5x=75
x=75/12.5
x=6
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3 years ago
show work please show work please show work please show work please show work please show work please show work please show work
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Answer:

Step-by-step explanation:

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4/5. try to make denominator 100. multiply both numerator and denominator by 20. 80/100. move decimal 2 spaces to the left. 0.8.

14/50. try to make denominator 100. multiply both numerator and denominator by 2. 28/100. 28%

0.19 can be written as 19/100. 19%

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2) If events A and B are DEPENDENT, then A) A and B must occur together. B) A and B cannot occur together. C) A's occurrence can
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Answer:

by 5

Step-by-step explanation: because tgey wou;d nred help

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