The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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Answer:
30
Step-by-step explanation:
Since there are 5 possible outcomes for the cards, and 6 possible outcomes for the die, there are a total of 5*6=30 outcomes possible. Hope this helps!
Answer:
Step-by-step explanation:
- The product of two matrices
and 
equals a matrix 
, where the first element of the subscript represents the amount of files of the matrix and the second element represents the amount of columns of the matrix. - Then, in this case
, therefore, its product will result a matrix 
. - Because C matrix is going to have an only file and three columns, we now have to find the values of the elements in each column, based on the elements of A and B.
- Commonly, to obtain the values of the resulting matrix, we just have to multiply each file of the first matrix by each column of the second matrix and sum, as follows:
- Finally, C matrix is
Answer:
top left questions answer is B
the area of the triangle is A
Volume of the cylinder is B
The area of the triangle for q 17 is A
