Question

In ΔABC, ∠A measures 132° and the values of b and a are 36 and 70, respectively. Find the remaining measurements of the triangle, and round your answers to the nearest tenth. ∠B = 82.2°, ∠C = 62.8°, c = 40.6 ∠B = 82.2°, ∠C = 62.8°, c = 30 ∠B = 22.5°, ∠C = 25.5°, c = 40.6 ∠B = 22.5°, ∠C = 25.5°, c = 30

Answer 1

Answer:

∠B = 22.5°, ∠C = 25.5°, c = 40.6

Step-by-step explanation:

I hope I helped you :D

Answer 2

Answer:

Step-by-step explanation:

You have an angle and 2 sides given. It just so happens that the angle is across from one of the sides. We can use the Law of Sines to find the missing angle B first.

$\frac{sin(132)}{70} =\frac{sinB}{36}$

and cross multiply to get

36 sin(132) = 70 sinB and

$\frac{36sin(132)}{70} =sinB$ and

sinB=.3821887674

In order to find a missing angle you will use the 2nd button on your calculator along with the sin button. When you do that you will see

$sin^{-1}($ and then enter the decimal and hit "enter". You will get that the missing angle B measures 22.5 rounded to the nearest tenth.

Now that you have angles A and B, you can find C using the Triangle Angle-Sum Theorem (that says that all the angles of a triangle have to add up to equal 180).

C = 180 - 132 - 22.5 so

C = 25.5 degrees

Now we can use the Law of Sines again with angle A and side A and angle C:

$\frac{sin(132)}{70} =\frac{sin(25.5)}{c}$ and

$c=\frac{70sin(25.5)}{sin(132)}$ and get that side c is 40.6

It is the third option there. Locate the third B and that's where you solution starts.