If a = first term and r = common ratio we have
a + ar + ar^2 = 13 and ar^2 / a = r^2 = 9
so r = 3
and a + 3a + 9a = 13
so a = 1
so they are 1,3 and 9
2.
in geometric series we have
4 , 4r ,4r^2 , 60
Arithmetic;
4, 4r , 4r + d , 4r + 2d
so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30
so d = 30 - 2r
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0
2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24
and the numbers are 4*3 = 12 , 4*3^2 = 36
first 3 are 4 , 12 and 36 ( in geometric)
and last 3 are 12, 36 and 60 ( in arithmetic)
The 2 numbers we ause are 12 and 36.
Answer:
Every class period is 43 minutes long.
Equation:
(m - 10) ÷ 4
We will find the inverse of the given functions:
y = x + 2 / x-2
(x-2) y = x + 2
-2y + xy = x + 2
-2y + xy = x + 2
x (y - 1) = 2 + 2y
x (y - 1) = 2 (y + 1)
x = 2 (y + 1) / (y - 1)
f (x) ^ - 1 = 2 (x + 1) / (x - 1)
The inverse is different.
f (x) = x + 1 / x-1
y = x + 1 / x-1
(x-1) y = x + 1
-y + xy = x + 1
x (y - 1) = 1 + y
x (y - 1) = (y + 1)
x = (y + 1) / (y - 1)
f (x) ^ - 1 = (x + 1) / (x - 1)
The inverse is the same.
Answer:
f (x) = x + 1 / x-1
f (x) ^ - 1 = (x + 1) / (x - 1)
f (x) = f (x) ^ - 1
Answer:
x=-36
Step-by-step explanation:
Add the 7/2x +1/2x to be 8/2x which means that it'll be 4x=18=9/2
then subtract 9/2x on both sides so itll be
-9/2x -9/2x
because if you do 8/2-9/2 it's -1/2
then multiply the reciprocal to both sides so
which then cancels out -1/2 and makes it
x=-36
Answer:
f−1(x)=ln(x+4)/ 2
Step-by-step explanation:
