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velikii [3]
3 years ago
10

Six machines, each working at the same constant rate, together can complete a certain job in 12 days. How many additional machin

es, each working at the same constant rate, will be needed to complete the job in 8 days?
Mathematics
1 answer:
Schach [20]3 years ago
7 0

Answer:

3 machine

Step-by-step explanation:

It is given that 6 machine each working at the same rate can complete the work in 12 days

We the has to complete in 8 days

Let we need x extra machine to complete the work in 8 days

So total number of machines =x+6

Now according to man work day equation M_1D_1=M_2D_2

6\times 12=(x+6)\times 8

8x+48=72

8x=24

x=3 machine

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Luda [366]

Answer:

y intercept =10

line y=-x+10

Step-by-step explanation:

Let y=mx+b is the required line.

<u>Slope of perpendicular lines :</u> If m_{1} and m_{2} be slope of two perpendicular lines. Them m_{1}\times m_{2}=-1

y=mx+b is perpendicular to y=x+10

the slope of y=x+10  is =1

m\times 1=-1\\m=-1

Hence eqn is y=-x+b

This equation passes through (15,-5)

-5=-15+b\\b=-5+15\\b=10

so the line is y=-x+10

<u>y-intercept :</u>

Substitute x=10

y=0+10\\y=10

7 0
3 years ago
1. 4&lt;7 Multiply both sides by 7, then by 6, then by 3, then by 10
erastova [34]

Answer:No, it didn't affect the inequality sign because we multiplied and divided by a negative number. In the 4th operation, the inequality sign changed because we divided by a negative number

Step-by-step explanation:

3 0
3 years ago
H(x)= (x^2 -36)/x +6 explain why the following function is not continuous at x=-6
sergeinik [125]

You can solve this problem through factoring.

First, you have the equation,

h(x) = \frac{x^2-36}{x-6}

Then, you can factor the numerator.

h(x) = \frac{(x+6)(x-6)}{x-6}

You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.

You are left with h(x) = x+6

The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.

8 0
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yulyashka [42]

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6 0
2 years ago
Which is a zero of the quadratic function f(x) = 16x?? + 32x - 9?
STALIN [3.7K]

Answer:

f(x) = 16x2 + 32x - 9

 

To find the "zeros", set f(x) = 0:

 

    0 = 16x2 + 32x - 9

 

The equation is solvable by factoring or by using the quadratic formula.  The factors (use the "ac" method) are:

 

    0 = (4x-1)(4x+9)

 

    x = 1/4 = 0.25 and x = -9/4 = -2.25

Step-by-step explanation:

6 0
3 years ago
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