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3 years ago

EASYY TO ANSWER I WILL MARK YOU AS BRILIANT HELP PLEASE

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

Question 1: (0,2) because b value in mx+b is y-intercept

Question 2: plug in 4 for x you will get 1 so max is (4, 1)

Question 3: plug in -4 for x you will get -5 so min is (-4, -5)

Hope it helps :D

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I need this equation solved

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Answer:

Step-by-step explanation:

similar triangles are proportional

and add all the sides of the bigger triangle

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2 years ago

A train goes 10 miles per hour. How far does it travel in 4 hours

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Answer:

40 mph

Step-by-step explanation:

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3 years ago

What is the domain and range of the relation shown in the table?

TEA [102]

Answer:

domain: {10,15,19,32}

range:{5,9,-1}

Step-by-step explanation:

As we know domain is the values of input and range is the values of output.

Here , x is the input and y is the output.

$\left[\begin{array}{cc}x&y\\10&5\\15&9\\19&-1\\32&5\end{array}\right]$

Thus the input values according to the given problem is : 10 ,15 , 19, and thus ,

⇒The domain would accordingly be these four numbers : 10 , 15 , 19 , 32.

Note that we donot have any information regarding the other values of x.

The range is : { 5,9,-1 } only as the 5 is repeated in two cases .

Range is unique and there must be not repetition. Thus the apt answer would be :

domain: {10,15,19,32}

range:{5,9,-1}

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3 years ago

Please help solve this system of equations

stepan [7]

Make a substitution:

$\begin{cases}u=2x+y\\v=2x-y\end{cases}$

Then the system becomes

$\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}$

Simplifying the equations gives

$\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}$

which is to say,

$\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}$

$\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81$

$\implies\dfrac uv=\pm27$

$\implies u=\pm27v$

Substituting this into the new system gives

$\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1$

$\implies u=\pm27$

Then

$\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13$

(meaning two solutions are (7, 13) and (-7, -13))

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3 years ago

Lisa used 1/4 cups of milk per batch using her muffin recipes. How many cups of Milan will she use when she made 6 batches of mu

marin [14]

Answer:

1 1/2

Step-by-step explanation:

1/4 cups * 6 batches = 1/4 * 6 = 6/4 = 1 2/4 = 1 1/2

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3 years ago