Answer:
Time : <u>7.96 s</u>
Distance Traveled : <u>357.8 m</u>
Explanation:
In order to solve this problem, we first consider the accelerated motion of rocket. We will be using the subscript 1 for accelerated motion.
So, for accelerated motion, we have:
Acceleration = a₁ = 14.5 m/s²
Time Period = t₁ = 3.1 s
Initial Velocity = Vi₁ = 0 m/s (Since, it starts from rest)
Final Velocity = Vf₁
Distance covered by sled during acceleration motion = s₁
Now, using 1st equation of motion:
Vf₁ = Vi₁ + (a₁)(t₁)
Vf₁ = 0 m/s + (14.5 m/s²)(3.1 s)
Vf₁ = 44.95 m/s
Now, using 2nd equation of motion:
s₁ = (Vi₁)(t) + (0.5)(a₁)(t₁)
s₁ = (0 m/s)(3.1 s) + (0.5)(14.5 m/s²)(3.1 s)
s₁ = 22.5 m
Now, we first consider the decelerated motion of rocket. We will be using the subscript 2 for decelerated motion.
So, for accelerated motion, we have:
Deceleration = a₂ = - 5.65 m/s²
Time Period = t₂ = ?
Initial Velocity = Vi₂ = Vf₁ = 44.95 m/s (Since, decelerate motion starts, where accelerated motion ends)
Final Velocity = Vf₂ = 0 m/s (Since, rocket will eventually stop)
Distance covered by sled during deceleration motion = s₂
Now, using 1st equation of motion:
Vf₂ = Vi₂ + (a₂)(t₂)
0 m/s = 44.95 m/s + (- 5.65 m/s²)(t₂)
t₂ = (44.95 m/s)/(5.65 m/s²)
<u>t₂ = 7.96 s</u>
Now, using 2nd equation of motion:
s₂ = (Vi₂)(t₂) + (0.5)(a₂)(t₂)
s₂ = (44.95 m/s)(7.96 s) + (0.5)(- 5.65 m/s²)(7.96 s)
s₂ = 357.8 m - 22.5 m
s₂ = 335.3 m
Thus, the total distance covered by sled will be:
Total Dustance = S = s₁ + s₂
S = 22.5 m + 335.3 m
<u>S = 357.8 m</u>
affect the the speed of water. If anything, it would be how high the wavelength's are. The higher the wavelengths are, the more that it would affect the speed, because there very high, but if it were to go longer on the width side, that would increase the speed, but that's not the case. Your correct answer would be (higher wavelength).