You can calculate potential energy by:
U = m.g.h
Where, U = potential energy
m = mass
g = acceleration due to gravity
h = height
Hope this helps!
To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

Here,
= Angle between areal vector and magnetic field direction.
According to Faraday's law, induced emf in the loop is,





At time
, Induced emf is,


Therefore the magnitude of the induced emf is 10.9V
I believe the correct answer is atmosphere (D).
The normal force is always perpendicular to the surface. So it would be straight to the left of the wall