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Anna007 [38]
3 years ago
6

What equations that have same solution as 2x-5=15

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0

Answer:

1(2x-5)=15

Step-by-step explanation: Following the steps of solving the equation, it results with the same answer.

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A bag contains 6 nickels and 14 pennies. What is the ratio, written in lowest terms, of nickels to the total number of coins in
VLD [36.1K]
There are 6 nickels and 14 pennies.
There are 20 total coins.

The ratio of nickels to coins is 6:20.
Both of these are divisible by 2, so we can reduce this to 3:10.
4 0
3 years ago
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26. -2, 3, 8, 13, 18,...
-Dominant- [34]

Answer:

each number is being added by 5

Step-by-step explanation:

5 0
3 years ago
Thankyou for all the help
Travka [436]

Answer:

1. x + y = 180

2. x = 50 y= 130

Step-by-step explanation:

They're parallel.

We can label the unamed angle z.

So z = y

and 50 = x

There's 360 degrees in a circle, so x + y= 180 because it's half 360 and half a circle.

x=50

so 50 + 50 = 100.

360 - 100 = 260

so 260 ÷ 2 = 130

y = 130 because y and z are equal so they're the same number

8 0
2 years ago
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Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
4 years ago
Sketch the graph of each rational function showing all the key features. Verify your graph by graphing the function on
Sonja [21]

Answer:

The graph crosses the x axis at x=0. For x> 0, it rises to a maximum value and then decreases toward y= 0 as x goes to infinity. For x< 0, it decreases to a minimum values then rises toward y= 0 as x goes to negative infinity. y= 0 is a horizontal asymptote but the graph crosses y= 0 at x= 0.

Step-by-step explanation:

A common mistake that students make is to think that a graph cannot cross a slant or horizontal asymptote. This is not the case! A graph CAN cross slant and horizontal asymptotes (sometimes more than once). It's those vertical asymptote critters that a graph cannot cross.

6 0
4 years ago
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