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Lemur [1.5K]
2 years ago
12

The question is in the picture. will give brainilist.​

Mathematics
1 answer:
Nuetrik [128]2 years ago
3 0

Answer:

y=2/5x-15

Step-by-step explanation:

y-y=m(x-x¹)

y-(-11)=2/5(x-10)

y+11=2/5x-4

-11 -11

y=2/5x-15

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Grace and her brother Sid want to raise money to go to band camp. Their parents have agreed to help them earn up to $400 by payi
LenKa [72]

Answer:

25m + 10b = 400

Step-by-step explanation:

Total amount that can be earned = $ 400

Amount earned on mowing a lawn = $ 25

Amount earned per hour on babysitting = $10

Amount earned for mowing one lawn is $ 25, so amount earned for mowing m lawns will be $ 25m

Amount earned for one hour of babysitting is $ 10, so amount earned for babysitting for b hours will be $ 10b

Total amount earned = Amount earned from mowing m lawns + Amount earned from babysitting for b hours

Using the values from above, we can set up the equation as:

400 = 25m + 10b

or

25m + 10b = 400

This equation represents the number of lawns they can mow, m, and hours they can babysit, b, to earn $400.

3 0
3 years ago
What Is the value of x
SCORPION-xisa [38]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
Find the slope of the line that passes through (2, 4) and (9,5).
givi [52]

Answer:

1/7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Evaluate the expressions for when x=-1, y=3, z=-2<br><br> z²+(x²)-y and x²(y²)(z²)
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the standard deviation of 21, 31, 26, 24, 28, 26
Vesnalui [34]

Given the dataset

x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}

We start by computing the average:

\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26

We compute the difference bewteen each element and the average:

x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}

We square those differences:

(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}

And take the average of those squared differences: we sum them

\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69

And we divide by the number of elements:

\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5

Finally, we take the square root of this quantity and we have the standard deviation:

\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39

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