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Furkat [3]
2 years ago
7

Pls. Help me solve with this math problem

Mathematics
2 answers:
Alchen [17]2 years ago
7 0
I think this is the answer...

Maksim231197 [3]2 years ago
3 0

Answer:

the answer is 15/28 so this is correct

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??????????????.??????
DIA [1.3K]
So in a cube, the width, length, and height are the same. Therefore, you have to find the cube root of 15.625 which is 2.5 and so the side length is 2.5
6 0
3 years ago
Which of the following inequalities matches the graph?
S_A_V [24]
X<-3 would be the answer
7 0
2 years ago
2
rusak2 [61]

Answer:

(1.13, 7.74) and (-4.13, 18.26)

Step-by-step explanation:

This can be solved in two ways:  mathematically and graphically.

<u>Graphing</u>

Plot both lines and find where they intersect.  See the attachment.

The intersection points are (1.13, 7.74) and (-4.13, 18.26)

<u>Mathematical</u>

y + 2x = 10

y = 10 - 2x

y = 3x² + 7x - 4

10 - 2x = 3x² + 7x - 4

3x² + 9x - 14 = 0

Solve this using the quadratic equation:

x = 1.13 and -4.13

Use these two values of x to find y:

y = 10 - 2x

y = 10 - 2(1.13)

y = 7.74

y = 10 -2x

y = 10 -2(-4.13)

y =  18.26

The two points are:

(1.13, 7.74) and (-4.13, 18.26)

7 0
2 years ago
Is the following shape a rectangle?how do you know?​
adelina 88 [10]

Answer:

The following shape is not a rectangle, but a square. I know this because the length and width are the same amount of square inch(feet, what ever the square counts for on your graph.) and rectangles width are typically longer than their length. However a square shares the same length and width,  

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Pixel goes shopping with one hundred dollars and ends up buying three different types of items: A, B, and C. The unit price of A
mixas84 [53]

Answer:

  • A - 16, B - 79, C - 5

Step-by-step explanation:

<u>Given</u>

  • A costs 5$
  • B costs  $0.25
  • C costs $0.05
  • A + B + C = 100
  • 5A + 0.25B + 0.05C = 100 ⇒ 100A + 5B + C = 2000

<u>Subtract the first equation from the second:</u>

  • 99A + 4B = 1900

<u>We have a restriction in numbers:</u>

  • 0 < A, B, C < 100

<u>Since 4B can be max 400, we get 99A > 1500  and 99A < 1900 so:</u>

  • A > 1500/99 > 15

and

  • A < 1900/99 < 19

A can be 16 or 18 as it should be even number to get B the whole number.

<u>If A = 16:</u>

  • 99*16 + 4B = 1900
  • 4B = 1900 - 1584
  • 4B = 316
  • B = 316/4 = 79

<u>If A = 18:</u>

  • 99*18 + 4B = 1900
  • 4B = 1900 - 1782
  • 4B = 118
  • B = 118/4 = 29.5, discarded as decimal

<u>So we get:</u>

  • A = 16, B = 79 and C = 100 - (16 + 79) = 5

<u>Let's proof the numbers:</u>

  • 16*5 + 79*0.25 + 5*0.05 = 100, confirmed

5 0
2 years ago
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