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Aneli [31]
3 years ago
14

How to solve the system of equations algebraically for all values of x, y, and z

Mathematics
1 answer:
stich3 [128]3 years ago
4 0
4x -3y + z = -10...............(1)
2x +y + 3z =  0...............(2)
-x +2y - 5z = 17...............(3)

First we multiply 3*(2) and add it to (1) 
6x +3y +9z =0..................+(1)..................> 10x + 10z = -10......(4)

Then we multiply -2*(2) and add it to (3) 
-4x -2y -6z =0 ...................+(3)................> -5x -11z = 17...........(5)

Multiply  2*(5) and add it to (4)
-10x -22z = 34...................+(4).................> -12 z = 24 ..............>>> z = -2

Substitute z in (4)............> 10x +10(-2) = -10.............................>>> x = 1

Substitute x and z in (2).....> 2(1) +y + 3(-2) =  0..................>>> y = 4

Solution (x,y,z) = (1,4,-2)

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Answer:

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Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

A meeting on an unpopular topic has been announced. The number of attendees may be modeled by X where:

P(X = x) = 1 / 2^(x+1), for x = 0,1,2,...

What is the probability that at least 5 people attend the meeting given that at least 2 attend?

The explanation of the answer is now provided as follows:

Given:

P(X = x) = 1 / 2^(x+1), for x = 0,1,2,...                    (1)

Since it is given that at least 2 attend, it implies that we need to calculate P(x) at x = 2.

Substituting x = 2 into equation (1), we have:

P(X = 2) = 1 / 2^(2 + 1)

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