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mina [271]
1 year ago
7

Simplify the exponential equation.

Mathematics
2 answers:
sergiy2304 [10]1 year ago
7 0

Answer: The answer is the last one

Step-by-step explanation:

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

Which makes b5 j2 j4.

To multiply powers of the same base, add their exponents. Add 2 and 4 to get 6.

Which gets you to b5 x j6.

So the last one is the answer

gavmur [86]1 year ago
4 0

Answer:

b^5 * j^6

Step-by-step explanation:

Well we can use the exponential identity: x^a*x^b=x^{a+b}

The base must be the same for this to work.

So let's combine like bases: (b^2*b^3)*(j^2*j^4)

We can simplify b^2 * b^3 using this identity to get: b^(2+3) = b^5

This gives us the equation: b^5*(j^2*j^4)

But to take a deeper look as to why this identity holds, let's represent b^2 and b^3 by what it really means: (b * b) * (b * b * b), so this is really just: b * b * b * b * b which can be simplified as an exponent: b^5, hopefully this helps you understand intuitively why this identity makes sense.

So using this identity, we can simplify j^2 * j^4 to j^6

This gives us the equation: b^5 * j^6

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Round to the nearest hundreth
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Answer:

∠ B ≈ 66.42°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos B = \frac{adjacent}{hypotenuse} = \frac{BC}{AB} = \frac{2}{5}, thus

B = cos^{-1}(\frac{2}{5} ) ≈ 66.42° ( to the nearest hundredth )

3 0
3 years ago
What is the greatest common factor c^2d^2​
Brums [2.3K]

Answer:

1

Step-by-step explanation:

Since there are no common prime factors, the only common factor for c²d² is 1, therfore it stays as is, c²d².

I am joyous to assist you anytime.

8 0
3 years ago
4p = 14.4<br> What is the value of p?<br> A. 3.6<br> B 3.8<br> C.10.4<br> D.57.6
4vir4ik [10]
The answer to your question is A.

answer: 3.6
6 0
2 years ago
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Sunny_sXe [5.5K]

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bzissssossisbs x9s s siss s sبسیسجسبسئسطسب،یز unsbsjsus

Step-by-step explanation:

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8 0
2 years ago
The rates of return on the investments in a large portfolio had mound shapeddistribution, with a mean of 20% and a standard devi
Scilla [17]

Answer:

a) 68% of the investments had a return of between 10% and 30%.

b) 32% of investments had a return that was either less than 10% or morethan 30%.

Step-by-step explanation:

We can use the Empirical Rule to solve this question:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean. This also means that 32% of the measures are more than 1 standard deviation from the mean.

95% of the measures are within 2 standard deviation of the mean. This also means that 5% of the measures are more than 2 standard deviations from the mean.

99.7% of the measures are within 3 standard deviations of the mean. This also means that 0.3% of the measures are more than 3 standard deviations from the mean.

In this problem, we have that:

Mean = 20%.

Standard deviation = 10%.

a. What proportion of the investments had a return of between 10% and 30%?

10 is the mean subtracted by 1 one standard deviation

30 is one standard deviation added to the mean.

So 10 and 30 are within 1 standard deviation of the mean. So 68% of the investments had a return of between 10% and 30%.

b. What proportion of investments had a return that was either less than 10% or morethan 30%?

This is the proportion of investments that were farther than one standard deviation of the mean.

By the Empirical Rule, 32% of investments had a return that was either less than 10% or morethan 30%.

6 0
3 years ago
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