Answer:

Step-by-step explanation:
Well we can use the exponential identity: 
The base must be the same for this to work.
So let's combine like bases: 
We can simplify b^2 * b^3 using this identity to get: b^(2+3) = b^5
This gives us the equation: 
But to take a deeper look as to why this identity holds, let's represent b^2 and b^3 by what it really means:
, so this is really just:
which can be simplified as an exponent:
, hopefully this helps you understand intuitively why this identity makes sense.
So using this identity, we can simplify j^2 * j^4 to j^6
This gives us the equation: 