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Aliun [14]
3 years ago
5

Which points are solutions??

Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0
A, C and E all work in the equations. In order for them to work, you must use the ordered pair in each of the three situations. Below is the work for all of the correct answers. 

Ordered Pair A : (1, -1)
y < x + 1
-1 < 1 + 1
-1 < 1 (TRUE)

y < 4
-1 < 4 (TRUE)

x < 6 
1 < 6 (TRUE)

Ordered Pair C : (4, 2)
y < x + 1
2 < 4 + 1
2 < 5 (TRUE)

y < 4
2 < 4 (TRUE)

x < 6 
5 < 6 (TRUE)

Ordered Pair E : (4, -2)
y < x + 1
-2 < 4 + 1
-2 < 5 (TRUE)

y < 4
-2 < 4 (TRUE)

x < 6 
4 < 6 (TRUE)
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The percents of students who travel to school by car, bus, and bicycle are shown for a school of 825 students. 20% by car 48% by
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24% could be going to school by walking

Step-by-step explanation:

4 0
3 years ago
Simplify the following expression. (52x + 61y) + (-6x + 47y)
kvv77 [185]

Answer:

46x + 108y

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

(52x + 61y) + (-6x + 47y)

<u>Step 2: Simplify</u>

  1. Combine like terms (x):                                                                                   46x + 61y + 47y
  2. Combine like terms (y):                                                                                   46x + 108y
3 0
3 years ago
Write the expression as an equivalent algebraic expression involving only x.
Kitty [74]

The given expression is \cos \left(2 \cos ^{-1} x\right)

We need to determine the expression as an equivalent algebraic expression involving only x.

The expression \cos \left(2 \cos ^{-1} x\right) has to be expressed as an algebraic expression in x.

Thus, we have;

\cos \left(2 \cos ^{-1} x\right)

Using the identity cos \ (2x)=2cos^2x-1 in the above expression, we get;

\cos \left(2 \cos ^{-1} x\right)=2\ cos^2(cos^{-1}x)-1

Simplifying, we get;

\cos \left(2 \cos ^{-1} x\right)=2[cos(cos^{-1}x)]^2-1

\cos \left(2 \cos ^{-1} x\right)=2(x)^2-1

\cos \left(2 \cos ^{-1} x\right)=2x^2-1

Hence, the expression \cos \left(2 \cos ^{-1} x\right) can be written as 2x^2-1

7 0
4 years ago
What is the answer to (4x+5)(4x-5)
dsp73

(4x+5)(4x-5) 
= 16x^2 - 25


4 0
4 years ago
Read 2 more answers
What are the common mulitples of 19 and 9
beks73 [17]
To get the least common multiplie (LCM) of 19 and 9 we need to factor each value first and then we chose all the factors which appear in any column and multiply them 19:9   9:33 and lcm:3319 the least common multiplie (LCM) is 3 multiplie by 3 multiplie by 19=171
4 0
3 years ago
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