4x = -36 Subtract 10 from both sides
x = -9 Divide by 4 on both sides
Step-by-step explanation:
<u>Step 1: Substitute x from the second equation into the second one</u>







<u>Step 2: Substitute y into the second equation</u>




Answer: 
y = x^2 -4x
x = -1
y = (-1)^2 - 4×-1=1+4 = 5
x= 0
y = (0)^2 - 4×0 = 0
x = 1
y = 1^2 -4×1 = 1-4 = -3
x = 2
y = 2^2 -4×2 = 4-8 = -4
x=3
y = 3^2 - 4×3 = 9-12 = -3
x = 4
y = 4^2 - 4×4 = 16 - 16 = 0
now 2nd equation
y = 2x^2 + x
x = -2
y = 2 (-2)^2 + (-2)= 8-2 = 6
x = -1
y = 2 (-1)^2+(-1)= 2-1 = 1
x = 0
y = 2(0)^2 +0 = 0
x = 1
y = 2 (1)^2 + 1 = 3
x = 2
y = 2(2)^2+2= 8 + 2 = 10
So easyies way is find all multiplues of 6 that are less than 50
6
12
18
24
30
36
42
48
and not 42
6
12
18
24
30
36
48
more than 25
30
35
48
do not have a 3 in them
48
the answer is 48