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Dmitry [639]
3 years ago
14

PLEASE HELP ME!!! PLEASE CORRECT ME IF I AM WRONG FOR THE FIRST ONE AND PLEASE DO THE SECOND ONE TOO!! THANK YOU!! :)

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

A = (a+b)/2

G = sqrt(ab)

Step-by-step explanation:

To find the arithmetic mean, we add the numbers together, then divide by how many numbers

A = (a+b)/2

To find the geometric mean, we multiply the numbers and take the nth root

G = (ab) ^ 1/2

G = sqrt(ab)

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GOAT is a parallelogram. Find the length of AG.
Scilla [17]

Answer:

AG = 16

Step-by-step explanation:

If you have a parallelogram, then the diagonals are bisected, meaning GS and SA are congruent, same with OS and ST. So, because 8 + 8 = 16, the length of AG = 16.

3 0
3 years ago
Geometry help please I'm stuck will give brainiest answer and thanks and five stars if correct
Tpy6a [65]
1. Reduction: 1/2
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8 0
4 years ago
Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing
MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

                = 6.08 + 6.08 + 8.60

                = 20.76

                ≈ 20.8 units

Therefore, amount of fencing required to cover the triangular park is 20.8 units.

3 0
3 years ago
Also on this one. I need to try and get a good grade on math cuz I have a C on math >3
aksik [14]

165,827 and 165,229



the hundreds spot in the first number is 8 while in the second number the hundreds spot is only two

7 0
3 years ago
What conclusion can be drawn from the quiz scores shown below?
Alex_Xolod [135]

Answer:

Ken class has a median of 84 while Judy class a median of 87

Step-by-step explanation:

Ken class has a median of 84 while Judy class a median of 87

7 0
3 years ago
Read 2 more answers
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