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Akimi4 [234]
3 years ago
6

(01.01 LC)

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:

C.  Use a straightedge to measure the length of the line segment.

Step-by-step explanation:

Two or more lines are said to be congruent when they are approximately equal in length to each other. Construction of congruent line segments involves some steps. And these steps require the use of appropriate constructing instruments and materials.

The given question gives options from which one is a correct step for constructing congruent line segments. The appropriate step from the options given is C.  A straightedge can be used to measure the length of the line segment.

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Answer: Independent because they have no outcomes in common


Step-by-step explanation:

The reason for this answer is because the event A is the first roll

And then you roll a 4 independently, they both do not control each other making it B because the outcomes can be totally different

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You are saving money to buy a new video game. You already have $12, and each week you save another $5. Which expression can you
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Help plezzzzzzzzzzzzz
Rus_ich [418]
C should be the answer. Hope this helps!

7 0
3 years ago
For each day enter the number of hours worked. Use the format shown in Model 1 and answer in terms of a reduced fraction.
natulia [17]
It is often easiest to use "military time". That is, add 12 to all the afternoon numbers and do the subtraction in the usual way. Of course, 1 hour = 60 minutes, so 10 minutes = 10/60 hour = 1/6 hour.

Mon: 15:10 -8:00 = 7:10 = 7 1/6

Tue: 15:25 -8:05 = 7:20 = 7 1/3

Wed: 14:30 -8:00 = 6:30 = 6 1/2

Thur: 14:45 -7:55 = 7:(-10) = 6:50 = 6 5/6

Fri: 15:38 -7:58 = 8:(-20) = 7:40 = 7 2/3

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Some calculators have nice features for working with degrees, minutes, and seconds. In this context, degrees and hours are the same thing. That is, the base-60 arithmetic is the same whether you consider the numbers to be hours or degrees. Similarly, some calculators convert nicely between decimal fractions and mixed numbers. In short, a suitable calculator will almost do this math for you. (You just need to add 12 to all the numbers in the column on the right.)
3 0
3 years ago
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

7 0
4 years ago
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