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3 years ago

Find the interest earned and the balance of the account: P=$650 R=4% T=2 Years

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

I have no idea.... Try to ask your teacher or your parents

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A yard is 3 times as long as it is wide. 176 feet of fencing is needed to enclose the yard. Find the dimensions of the yard

svet-max [94.6K]

The perimeter of a rectangle is twice the sum of its side lengths.

P=2(L+W), we are told that L=3W and P=176 so

2(3W+W)=176

2(4W)=176

8W=176

W=22 ft, since L=3W

L=66 ft

So the yard is 22 feet wide and 66 feet long.

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3 years ago

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93 divided by 3 using repeated subtraction

Naily [24]

93/3=31 Answer is 31

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3 years ago

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Cubed root x cubed root x2

Yuki888 [10]

Answer:

Final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$

Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

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3 years ago

What is the common ratio for the geography sequence? -15,-9,-27/5,-81/25

Reptile [31]

1000 j etyuu was the night of my school week I am so

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3 years ago

Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.

trasher [3.6K]

Answer:

$\frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

Step-by-step explanation:

Given the integral equation

$\int\limits{xe^{7x}} \, dx \\$

According to integration by part;

$\int\limits {u} \, dv = uv + \int\limits {v} \, du$

u = x, dv = e^7x

du/dx = 1

du = dx

$v = \int\limits {e^{7x}} \, dx \\v = e^7x/7$

Substitute the given values into the formula;

$\int\limits {xe^{7x}} \, dx = x(e^{7x}/7) + \int\limits ({e^{7x}/7}) \, dx\\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{7*7} \\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

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3 years ago