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Annette [7]
3 years ago
10

Halla las dimensiones de un rectángulo de 48 cm2 de área sabiendo que es 2 cm más ancho que alto

Mathematics
1 answer:
Sloan [31]3 years ago
7 0

Answer:Alto 16cm Ancho 32cm

A+2A=48

3A=48

/3

A=16

Step-by-step explanation:

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Think of one leg of a right triangle is 21' and the length of the hypothenuse is 29' what is the length of the other leg
Ksivusya [100]

Answer:

length of other leg = 20'

Step-by-step explanation:

Given:

One leg of triangle let it be base of triangle = 21'

Hypotenuse = 29'

To Find:

Third leg =perpendicular = ?

Solution:

Given is a right angled triangle with two of its sides given to us

We have Pythagoras theorem for right angled triangle and according to it

Pythagoras theorem is

for a right angled triangle

(hyp) ² = (perp)²+(base)²

We have the values of hyp and base

putting them in the equation we get

(29) ² = (perp) ²+(21) ²

841 = (perp) ² + 441

subtracting 441 from both sides we get

841 - 441 = (perp) ² + 441 - 441

400 =  (perp)²

or

(perp) ²=400

Taking square root of both sides

\sqrt{(perp)^{2} }=\sqrt{400}

it gives us

perp = ± 20'

As it is length and it can not be negative so

perp = 20'

or

length of other leg = 20'

3 0
3 years ago
What happens to the value of the expression 80/h as h increases from a small positive number to a large positive number?
Alex787 [66]

Answer:

The numerator decreases when the denominator increases

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which is equivalent to V180x11 after it has been simplified completely?
inna [77]

Question:

Which is equivalent to \sqrt{180x^{11}} after it has been simplified completely?

Answer:

\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}

Step-by-step explanation:

Given

\sqrt{180x^{11}}

Required

Simplify

We start by splitting the square root

\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}

Replace 180 with 36 * 5

\sqrt{180x^{11}} = \sqrt{36 * 5} *  \sqrt{x^{11}}

Further split the square roots

\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} *  \sqrt{x^{11}}

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{11}}

Replace power of x; 11 with 10 + 1

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10 + 1}}

From laws of indices; a^{m+n} = a^m * a^n

So, we have

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10} * x^1}

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10} * x}

Further split the square roots

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10}} * \sqrt{x}

From laws of indices; \sqrt{a} = a^{\frac{1}{2}}

So, we have

\sqrt{180x^{11}} = 6*\sqrt{5} *  x^{10*\frac{1}{2}} * \sqrt{x}

\sqrt{180x^{11}} = 6*\sqrt{5} *  x^{\frac{10}{2}} * \sqrt{x}

\sqrt{180x^{11}} = 6*\sqrt{5} *  x^{5} * \sqrt{x}

Rearrange Expression

\sqrt{180x^{11}} = 6 *  x^{5} * \sqrt{5} * \sqrt{x}

\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}

From laws of indices; \sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}

So, we have

\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}

\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}

\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}

<em>The expression can no longer be simplified</em>

Hence, \sqrt{180x^{11}} is equivalent to 6x^{5}\sqrt{5x}

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3 years ago
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Which of the following ordered pairs is a solution of the line y-2x=6
Novay_Z [31]

<u><em>Answer:</em></u>

<u><em>x = -3 + Y/2</em></u>

<u><em>y= 6 +  2x</em></u>

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The personnel director at a large company studied the eating habits of the company's employees. The director noted whether emplo
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Answer:A designed experiment

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