Question

Multiply the binomial and the trinomial. (x-2)(x^2+2x+4)

Answer 1

Answer:

Step-by-step explanation:

To solve this problem, we need to multiple $x$ and -2 by $x^{2} + 2x + 4$ and add the results together:

$x(x^{2} + 2x + 4)$

$x^{3} + 2x^{2} + 4x$

$-2(x^{2} + 2x + 4)$

$-2x^{2} - 4x - 8$

Adding the two together give the following:

$(x^{3} + 2x^{2} + 4x) + (-2x^{2} - 4x - 8)$

$x^{3} - 8$