Ok i need this like really
2 answers:
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Answer:
Step-by-step explanation:
Let X be the length of pregnancy.
X is N(268, 15)
a) Prob of pregnancy lasting 307 days or longer
= P(X>307) =
=0.5-0.4953
=0.0047
b) Lowest 2% is 2nd percentile
Z=-2.55
X score = 268-2.55(15)
= 229.75 days
If length of days >230 days then it is not premature.
Answer:
Amount of fencing required = 75 yards
Step-by-step explanation:
Distance between the two points and
is given by the formula,
d =
Distance between A(3, 6) and B(3, -2) =
= 8 yards
Distance between B(3, -2) and C(-7, 4) =
=
= 11.66 ≈ 12 yards
Distance between C(-7, 4) and D(-7, -2) =
= 6 yards
Distance between D(-7, -2) and E(-3, -2) =
= 4 yards
Distance between E(-3, -2) and F(-3, -8) =
= 6 yards
Distance between F(-3, -8) and G(3, -8) =
= 6 yards
Distance between G(3, -8) and H(10, -12) =
=
=
= 8.06 ≈ 8 yards
Distance between H(10, -12) and J(10, 6) =
= 18 yards
Distance between A(3, 6) and J(10, 6) =
= 7 yards
Since length of fence required = perimeter of the flat area
Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7
= 75 yards
Therefore, amount of fencing required = 75 yards