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3 years ago

ASAP!!!! ILL GIVE BRAINIEST

Chemistry

2 answers:

scoundrel [369]3 years ago

8 0

1st fission event

n + fission reactant -> fission product + n + n

so the 2 n created can initiate 2 new reactions

2nd fission event, for each n

n + fission reactant -> fission product + n

so the 1 n created can initiated 1 new reaction

In 1st event 2n are created.

In 2nd event, the 2n from 1st created 1n each for a total of 2n.

combining both events, 2n + 2n = 4n are produced in total.

umka2103 [35]3 years ago

5 0

1. answer is 2

2. answer is 1

3. answer is 3.

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Which of the following elements can form diatomic molecules held together by triple covalent bonds?

Art [367]

Nitrogen can form a diatomic molecule held together by triple bonds.

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2 years ago

Read 2 more answers

Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,

vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

$N=n\times N_A$

Where : N = Number of atoms

n = moles

$N_A=6.022\times 10^{23}$ = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol × 44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol × 8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol

Mass percentage of gold :

$\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=33.35 \%$

Mass percentage of silver:

$\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=62.80\%$

Mass percentage of copper :

$\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=3.85\%$

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vova2212 [387]

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