Answer:
11/12 full
Explanation:
The correct question is
Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 2/3 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what fraction of its capacity?
A) 3/4
B) 5/6
C) 11/12
D) 7/6
E) 11/6
Solution
Let Capacity of Drum X = 150L
and Drum Y = 300L
Oil in Drum X = 75 L
Oil in Drum Y = 2/3 * 300 = 200L
Oil poured in to Drum Y => Oil in Drum Y = 275L
Capacity Ratio = 275/300 = 11/12
Staggered conformers are lower in energy than eclipsed conformers , Option A is the right answer.
<h3>What are Eclipsed and Staggered Confirmation ?</h3>
The arrangement of atoms in molecule such that the dihedral angle formed is 60 degree is called Staggered Conformation and the arrangement of atoms in which the dihedral angle is 0 degree is called Eclipsed Confirmation
Among the given statements
The statement that best describe the stability of Staggered Conformers and eclipsed conformers is Staggered conformers are lower in energy than eclipsed conformers .
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This reaction is called an exothermic reaction.
If the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.
<h3>What is the Gibbs Free Energy?</h3>
The Gibb Free Energy is used to obtain the feasibility of a reaction. If the Gibbs free energy is positive the reaction is not spontaneous. If the value is negative, the reaction is spontaneous while a zero values indicates equilibrium.
From the equation;
ΔG = ΔH - TΔS, it follows that if the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.
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Answer:
552 g of LiNO₃
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 2 L
Molarity of LiNO₃ = 4 M
Mass of LiNO₃ =?
Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:
Volume of solution = 2 L
Molarity of LiNO₃ = 4 M
Mole of LiNO₃ =?
Molarity = mole /Volume
4 = mole of LiNO₃ / 2
Cross multiply
Mole of LiNO₃ = 4 × 2
Mole of LiNO₃ = 8 moles
Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:
Mole of LiNO₃ = 8 moles
Molar mass of LiNO₃ = 7 + 14 + (16×3)
= 7 + 14 + 48
= 69 g/mol
Mass of LiNO₃ =?
Mole = mass /Molar mass
8 = Molar mass of LiNO₃ /69
Cross multiply
Molar mass of LiNO₃ = 8 × 69
Molar mass of LiNO₃ = 552 g
Thus, 552 g of LiNO₃ is needed to prepare the solution.
