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Ne4ueva [31]
3 years ago
9

If you were to place the beaker containing the products of the reaction between copper ii chloride and aluminum on a balance, ho

w would the mass of these products compare to the mass of the initial reactants. explain your answer.
Chemistry
1 answer:
Allisa [31]3 years ago
6 0
The mass would be same because of the law of conservation which states that the mass of the reactants must equal to the mass of products
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The correct answer would be the last option.  The property that is common to all group 2 elements is that they  tend to form ionic bonds by losing electrons making these atoms positive charge. They are called cations. These elements are beryllium, magnesium, calcium, strontium, and radium. 
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A gas at 325 k has a volume of 4.0 L. If the gas’s volume changes to 2.0 L at constant pressure, what will be the new temperatur
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Write a mechanism for the esterification of propanoic acid with 18O-labeled ethanol. Show clearly the fate of the 18O label. (b)
tatuchka [14]

Answer:

See explanation and images attached

Explanation:

a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.

b)  In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.

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3 years ago
Ce cantitate de O se gaseste in 5,8 g hidroxid de magneziu
coldgirl [10]

Answer:

separare pâlnii de picurare balon cotat. 1. 2. 3. 4 5 6 7. 8. 9. 1 ... Mod de lucru: 25 g Na2SO4∙7H2O se dizolvă în cantitatea minim ... Exemple: NaOH – hidroxid de sodiu.

Explanation:

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3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
3 years ago
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