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lianna [129]
4 years ago
6

Which material is a material is mixture

Chemistry
2 answers:
Sav [38]4 years ago
7 0

Answer:

A heterogeneous mixture is a mixture of two or more chemical substances (elements or compounds). Examples are: mixtures of sand and water or sand and iron filings, a conglomerate rock, water and oil, a portion salad, trail mix, and concrete (not cement).

Explanation:

kondaur [170]4 years ago
6 0
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Featured snippet from the web
A mixture is two substances mixed together but not bonded together. Methane is CH4, so again it is bonded together so again it is not a mixture. Magnesium is just an element so there is nothing mixed in it since it is a pure substance. So the answer is Air since it is a mixture of gases.
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Which way of dissolving changes the chemical identity of the solute?
sasho [114]

Answer:

Ionization and dissociation

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3 years ago
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Find mass of 3 moles of water​
EleoNora [17]

Answer:

54 g

Explanation:

1 mole of water = H2O

mass of 1 mole of H2O= mass of h2 + mass of o

= 2× mass of h +mass of o

= 2×1+16 =18 g

1 mole of water = 18g

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3 years ago
What type of chemical reaction is CaCaI2 + F2 = CaF2 + CI2
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Answer:

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5 0
4 years ago
How can we find the number of moles in equilibrium?
pychu [463]
<span>You can find the number of moles in equilibrium if you got the chemical reaction correctly. Make sure that you got the exact chemical formula of the substance that is reacting and the yielded product. If you got them, balance the chemical reaction. If the chemical reaction is balanced, the system is in equilibrium. You can find the number of moles in equilibrium at the coefficients of the chemical substances you are balancing. For example, N2 + 3H2 -> 2NH3. The number of moles of N2 is 1, H2 is 3 and NH3 is 2.</span>
5 0
3 years ago
In going from room temperature (25 C) to 10 C above room temperature, the rate of reaction doubles. Calculate the activation ene
Sauron [17]

Answer:

Ea=5.29 × 10⁴ J/mol

Explanation:

In going from 25 °C (298 K) to 35 °C (308 K), the rate of the reaction doubles. Since the rate of the reaction depends on the rate constant (k), this implies that the rate constant doubles. We can find the activation energy (Ea) using the two-point form of the Arrhenius equation.

ln\frac{k_{2}}{k_{1}} =\frac{-Ea}{R} .(\frac{1}{T_{2}}-\frac{1}{T_{1}})\\ln\frac{2k_{1}}{k_{1}}=\frac{-Ea}{8.314J/K.mol}.(\frac{1}{308K}-\frac{1}{298K} )\\Ea=5.29 \times 10^{4} J/mol

8 0
3 years ago
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