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4 years ago

8

What is the magnitude of the dipole moment formed by separating a proton and an electron by 85 pm ?

1 answer:

Marina CMI [18]4 years ago

6 0

<span>p=q x D = 1.6 x 10^- 19x85x 10^-12 = 3.7 D</span>

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Crossword please help must finish in 15 mins

kogti [31]

Across:

10. The circulatory system transfers nutrients, gases, liquids, and heat around the body.

11. The circulatory system transports heat, which helps regulate temperature.

13. The place where oxygen enters the blood and carbon dioxide leaves the blood. Lungs.

15. A gas that is transported in arteries from the lungs to the rest of the body via the heart. Oxygen.

Down:

2. The heart, blood, and vessels. Circulatory System.

4. Blood in arteries is bright red because it is rich in oxygen.

6. A waste gas that is transported in veins from the body to the lungs via the heart. Carbon di Oxide.

<u>Explanation:</u>

The circulatory system includes blood vessels, blood, and heart. This system provides the body tissues with oxygen and some nutrients. It also carries hormones and eliminates needless waste products.

This transportation takes place between the cells via blood throughout the body. The channel that blood passes through is a blood vessel that is pumped by an organ called heart. The heart directs the blood passing all over the body.

The lungs are a duo of air-filled, spongy organs positioned on both sides of a human's chest. Its main function is to take in air present in the atmosphere and transfer oxygen to the bloodstream. From where it gets circulated throughout the body.

6 0

3 years ago

A hypothetical AX type of ceramic material is known to have a density of 3.55 g/cm3 and a unit cell of cubic symmetry with a cel

postnew [5]

Explanation:

For AX type ceramic material, the number of formula per unit cells is as follows.

$\rho = \frac{n'(A_{c} + A_{A})}{V_{C}N_{A}}$

or, $n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}$

where, n' = no. of formula units per cell

$A_{c}$ = molecular weight of cation = 90.5 g/mol

$A_{a}$ = molecular weight of anion = 37.3 g/mol

$V_{c}$ = volume of cubic cell = 3.55 $g/cm^{3}$

a = edge length of unit cell = $3.9 \times 10^{-8} cm$

$N_{A}$ = Avogadro's number = $6.023 \times 10^{23}$

$\rho$ = density = 3.55 $g/cm^{3}$

Now, putting the given values into the above formula as follows.

$n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}$

= $\frac{3.55 g/cm^{3} \times (3.9 \times 10^{-8})^{3} \times 6.023 \times 10^{23}}{(90.5 + 37.3)}$

= 0.9

= 1 (approx)

Therefore, we can conclude that out of the given options crystal structure of cesium chloride is possible for this material.

3 0

3 years ago

What is the molality of the resulting solution when 15.0 g of Licl is combined with 105 g of water? 0/1 point 0 1.42 m 2.95 m 3.

xenn [34]

Answer:

3.37 m

Explanation:

<u>Number of moles of solute present in 1 kg of solvent is termed as molality</u>

It is represented by 'm'.

Thus,

$Molality\ (m)=\frac {Moles\ of\ the\ solute}{Mass\ of\ the\ solvent\ (kg)}$

Given that:

The mass of LiCl = 15.0 g

Molar mass of LiCl = 42.394 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{15.0\ g}{42.394\ g/mol}$

$Moles= 0.3538\ mol$

Mass of the solvent = 105 g

Also, 1 g = 0.001 g

So,

Mass of water (solvent) = 0.105 kg

Molality is:

$Molality\ (m)=\frac {0.3538}{0.105}\ m$

<u>Molality = 3.37 m</u>

3 0

3 years ago

Explain the following: Unless the loss of reactant is extreme, only the loss of limiting reactant mass truly introduces error in

natita [175]

Answer:

我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈

Explanation:

我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈

6 0

3 years ago

in general, as the temperature increases, the solubility of gases in water ____ and the solubility of most solids in water___

saul85 [17]

Answer:

in general, as the temperature increases, the solubility of gases in water <u>decreases</u> and the solubility of most solids in water <u>increases</u>.

4 0

3 years ago