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3 years ago

8

What is the magnitude of the dipole moment formed by separating a proton and an electron by 85 pm ?

1 answer:

Marina CMI [18]3 years ago

6 0

<span>p=q x D = 1.6 x 10^- 19x85x 10^-12 = 3.7 D</span>

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Which of the following statements regarding glucose is FALSE?a) Glucose is the main component of starch and glycogen.b) Glucose

marishachu [46]

Answer:

The correct option is C.

Explanation:

Carbohydrates are one of the macro molecules that are consumed by living organisms. The end product of carbohydrate is glucose. Glucose is a very important fuel that the body cells used to produce energy, which they use to carry out their daily activities. Glucose is also known as blood sugar and it is the only fuel that living cells can use for the production of ATP. Other food macro molecules such as lipids and proteins can also be converted to glucose if there is a need for that. Glucose is always stored in the body in form of glycogen.

The statement given in option C about glucose is wrong because glucose is a monosaccharide and not a disaccharide.

8 0

3 years ago

The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut

aivan3 [116]

Answer:

$Molarity=1.22\ M$

Explanation:

Given:

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (19 + 273.15) K = 292.15 K

Volume = 0.200 L

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K

⇒n = 0.008174 moles

From the reaction shown below:-

$H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O$

1 mole of $H_2SO_4$ react with 2 moles of $NaOH$

0.008174 mole of $H_2SO_4$ react with 2*0.008174 moles of $NaOH$

Moles of $NaOH$ = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.016348}{0.0134}\ M$

$Molarity=1.22\ M$

8 0

2 years ago

In terms of bonds what would the molecule C6H12 be classified as

docker41 [41]

It has a double C=C bond so that means it's unsaturated, but it can also be a cyclic compound with only simple C-C bonds

5 0

2 years ago

Predict the products and then balance the equation

Aneli [31]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the balanced equation for given Double displacement reaction ~

$\sf Pb(NO_3)_2 +2 \: KI = PbI_2 +2 \: KNO_3$

The products fored are : Lead Iodide ( PbI2 ) and Potassium Nitrate ( KNO3 )

4 0

2 years ago

Read 2 more answers

Bugaboo can be oxidised to a carboxylic acid by heating with acidified potassium manganate (VII). Give the name and structural f

Novosadov [1.4K]

Answer:

See below.

Explanation:

CH3CH2CH2CH2OH is butanol.

The carboxylic acid formed , butyric acid has the formula:

CH3CH2CH2COOH.

Structural formula:

H H H O

| | | ||

H - C - C - C - C - OH

| | |

H H H

8 0

3 years ago