The concentration of iron in ppb is 5.2 ppb
In atmospheric chemistry, PPM( parts per million) and PPB( parts per billion) units are used to express the concentration of gases. PPB stands for parts per billion, while PPM stands for parts of gas per million parts of air.
2.6 × 10⁻⁶ grams of iron in 500 ml of water.
Now, converting milliliter into liter:
500 mL = 500 mL × ( 1L / 1000 mL ) = 0.5 L
Now for ppm, mass must be in mg.
2.6 × 10⁻⁶ grams = 2.6 × 10⁻⁶ grams × ( 1000 mg / 1 grams ) = 2.6 × 10⁻³ mg
Then, the concentration of iron in ppm will be:
2.6 × 10⁻³ mg / 0.5 L = 5.2 × 10⁻³ ppm
Now, 1 ppm = 1000 ppb
Therefore,
5.2 × 10⁻³ ppm × 10³ = 5.2 ppb
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Answer:
39.3%
Explanation:
CaF2 + H2SO4 --> CaSO4 + 2HF
We must first determine the limiting reactant, the limiting reactant is the reactant that yields the least number of moles of products. The question explicitly says that H2SO4 is in excess so CaF2 is the limiting reactant hence:
For CaF2;
Number of moles reacted= mass/molar mass
Molar mass of CaF2= 78.07 g/mol
Number of moles reacted= 11g/78.07 g/mol = 0.14 moles of Calcium flouride
Since 1 mole of calcium fluoride yields two moles of 2 moles hydrogen fluoride
0.14 moles of calcium fluoride will yield 0.14×2= 0.28 moles of hydrogen fluoride
Mass of hydrogen fluoride formed (theoretical yield) = number of moles× molar mass
Molar mass of hydrogen fluoride= 20.01 g/mol
Mass of HF= 0.28 moles × 20.01 g/mol= 5.6 g ( theoretical yield of HF)
Actual yield of HF was given in the question as 2.2g
% yield of HF= actual yield/ theoretical yield ×100
%yield of HF= 2.2/5.6 ×100
% yield of HF= 39.3%
They are a relatively recent invention.
I hope it was helpful for you.
Is soluble in water but not soluble in acetonitrile.
So i think its false
(35 kg)*(1000 g / 1 kg)
(35 kg / 1 kg)*(1000 g)
kg units cancel, you're left with units of g
35/1*1000 = 35,000
ANSWER:
35,000 g
