Answer:
It would be 6
Step-by-step explanation:
Answer:
To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.
Step-by-step explanation:
A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.
This polynomial has roots -4, -1, and 5. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.
In this polynomial:
Root -4 has even multiplicity of 4 so it only touches and does not cross through.
Root -1 has odd multiplicity of 3 so crosses through.
Root 5 has even multiplicity of 6 so it only touches and does not cross through.
Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.
To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.
Answer:
Option A) Inside the circle
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The radius is equal to the distance from the center to any point on the circle
the formula to calculate the distance between two points is equal to
we have
A(-5,-8),M(-1,-3)
substitute the values
step 2
Find the distance from the center to point V
we know that
If the distance from the center to point V is equal to the radius, then the point V lie on the circle
If the distance from the center to point V is less than the radius, then the point V lie inside the circle
If the distance from the center to point V is greater than the radius, then the point V lie outside the circle
we have
A(-5,-8),V(-11,-6)
substitute in the formula
so
The distance from the center to point V is less than the radius
therefore
The point V lie inside the circle
Hope that helped :)
h^2 - 12h + 20 can be factored to:
(h-10)(h-2)
These cannot be zero so, h cannot be 10 or 2.
