These 3 points form a triangle.
Find the perpendicular bisector of each side.
The point where all 3 perpendicular bisectors intersect is the point that is equidistant from all 3 gates.
Look at the image to help you out.
Have an awesome day! :)
Answer:
clc
clear all
close all
format long
[email protected](n) sum((1:n).^4);
n=1:6;
A=[n(:).^5 n(:).^4 n(:).^3 n(:).^2 n(:) ones(numel(n),1)];
b=[f(1);f(2);f(3);f(4);f(5);f(6)];
C=A\b;
for i=5:-1:0
fprintf('c%d = %f\n',i,C(5-i+1))
end
Answer:
BOB BOB BOB BOBBY DEE BOB SHE SB ON MY BOB AND DID NOT SAY SORRY oh and it's B
I believe it is 8x.
Use the formula A=1/2(b*h)
A=1/2(4x(5x-1))
A=1/2(20x-4x)
A=1/2(16x)
A=8x