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Setler79 [48]
2 years ago
7

Solve: y= 7/3x-3 and y=11

Mathematics
2 answers:
anastassius [24]2 years ago
7 0

Answer:

Step-by-step explanation:

y =\frac{7}{3}x -3\\\\\frac{7}{3}x-3=11\\\\

Add 3 to both the sides,

\frac{7}{3}x-3+3=11+3\\\\\frac{7}{3}x+0=14\\

Now multiply both sides by 3

3*\frac{7}{3}x=14*3\\\\

7x = 42

Divide both sides by 7

\frac{7x}{7}=\frac{42}{7}

x= 6

Travka [436]2 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

Given

y = \frac{7}{3} x - 3 and y = 11, thus

\frac{7}{3} x - 3 = 11 ( add 3 to both sides )

\frac{7}{3} x = 14

Multiply both sides by 3 to clear the fraction

7x = 42 ( divide both sides by 7 )

x = 6

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

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Answer:

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Step-by-step explanation:

The question talks about;

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We are required to determine the length of the diagonal

To answer the question, we need to know the following;

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