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9966 [12]
4 years ago
13

3/5÷33/5 find the quotient​

Mathematics
1 answer:
defon4 years ago
7 0
Flip 33/5

3/5 times 5/33
3 times 5 /5 times 33
15/165
Reduce
1/11
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Harriet rode her bike 2 1/4 miles to the mall. She then rode 3/4 mile to the grocery store. She came back the way she went. How
vlabodo [156]
In order to solve this problem you have to add the distance Harriet traveled away from her starting point which is 2 1/4+3/4. Then you should end up with 3 miles. After that it says she went back on the same route so you have to double the distance. So in total she rode 6 miles.
4 0
3 years ago
Read 2 more answers
Use your device keyboard to enter x+1= 7 in the box.<br>Check Answer​
egoroff_w [7]
<h2>ANSWER:</h2>

_______________________________________________________

Answer is x = 6

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<h2>EXPLANATION:</h2>

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We know that 7 - 1 is 6. 6 is what x equals because 7 - 1 is 6 and 6 + 1 is equal to 7.

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7 0
3 years ago
What is the slope of a line that is perpendicular to the line y = 1?
Katyanochek1 [597]
The line        Y = 1    is a horizontal line; its slope is zero.

A line perpendicular to   Y = 1   is a vertical line.
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The slope of a vertical line is undefined.  It doesn't have
a name or a symbol.  It's nothing.)
3 0
3 years ago
A gift box has the shape of a cube with an edge length of 4.5 in.
DIA [1.3K]

Answer:

4.5 times 4.5 times 4.5 = 91.125

Step-by-step explanation

To find the volume you do v= length times width times height.

6 0
3 years ago
Read 2 more answers
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
4 years ago
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