Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
B is 90-42=48° since complementary angles add to 90°
Answer:
the y-intercept is (0,-6)
the x-intercept is (8,0)
Step-by-step explanation:
<em>Solving for the y-intercept:</em>
Since the equation 'y=3/4x - 6' is in the 'y=mx + c' form (where m is the slope and c is the y-intercept):
3/4 is m (which is the slope)
-6 is c (which is the y-intercept)
<em>Solving for the x-intercept:</em>
When the line intersects with the x-axis, the y-value is 0. Hence, the coordinate is (x,0). Substituting this into 'y=3/4x - 6':
0 = 3/4x - 6
3/4x - 6 + 6 = 6
3/4x = 6
x = 4/3 * 6
= 8
Hence,
the y-intercept is (0,-6)
the x-intercept is (8,0)
<em>Hope this helps and be sure to have a wonderful time ahead at Brainly! :D</em>
Answer:
Formula of range is HIGHEST VALUE - LOWEST VALUE....
