The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
Answer:
csc
A
, as desired!
Step-by-step explanation:
cos
2
A
sin
A
+
sin
2
A
cos
A
,
=
cos
2
A
cos
A
+
sin
2
A
sin
A
sin
A
cos
A
,
=
cos
(
2
A
−
A
)
sin
A
cos
A
,
=
cos
A
sin
A
cos
A
,
=
1
sin
A
,
=
csc
A
, as desired!
Answer:
Answer is 9
Step-by-step explanation:
Remember PEMDAS???
"parenthesis, exponents, multiplication, division, addition, subtraction"
you would first solve the addition inside of the parentheses (1 + 2 = 3), and from there finish the equation as it's written from left to right.
I think the answer would be 38in^2
Because the equation is : (a+b) *h / 2
A and b are both the bases of the trapezium
So (11 + 8) these are the bases and the height is 4 so you would do
(11+8)*4 / 2
(19)*4 / 2
76 / 2
= 38