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horrorfan [7]
3 years ago
5

You're studying how well students remember vocabulary after they stop studying a new language. The first student you study remem

bers 95% of the
French words she learned 3 months later, but only 70% of the words 12 months
later.
Before studying more students, you wonder: Is a decreasing linear model or an
exponential decay model likely to be a better fit for data about remembering?
Decide which model you think will be better. Explain your reasoning.
Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

Exponential decay model

Step-by-step explanation:

A quick graph shows the remembrance pattern is not linear because the slope is not the same. Therefore a very likely remembrance pattern will be exponentially related.

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Evaluate ∫SF⃗ ⋅dA⃗ , where F⃗ =(bx/a)i⃗ +(ay/b)j⃗ and S is the elliptic cylinder oriented away from the z-axis, and given by x2/
Norma-Jean [14]

Answer:

Therefore surface integral is \pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c.

Step-by-step explanation:

Given function is,

\vec{F}=\frac{bx}{a}\uvec{i}+\frac{ay}{b}\uvec{j}

To find,

\int\int_{S}\vec{F}dS  

where S=A=surfece of elliptic cylinder we have to apply Divergence theorem so that,

\int\int_{S}\vec{F}dS

=\int\int\int_V\nabla.\vec{F}dV

=\int\int\int_V(\frac{b}{a}+\frac{a}{b})dV  

=\frac{a^2+b^2}{ab}\int\int\int_VdV

=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}

=\frac{a^2+b^2}{ab}\times \pi ab\times 2c=\pi (a^2+b^2)c

  • If unit vector \cap{n} directed in positive (outward) direction then z=c and,

\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1} . dA      

=\int\int_{S_1}.dA=0

  • If unit vector \cap{n} directed in negative (inward) direction then z=-c and,

\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA      

=\int\int_{S_2}. -dA=0

Therefore surface integral without unit vector of the surface is,

\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c

5 0
4 years ago
Last Saturday, the average temperature was 8% higher than the average temperature, 2 Sundays ago, the average temperature 2 Sund
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⇒ The average temperature last Sunday

Since 8%=0.08

Therefore, The average temperature last Sunday

⇒ The average temperature last Sunday

⇒ The average temperature last Sunday

⇒ The average temperature last Sunday

Thus, the right option is 1.08T and (1+8/100)T

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3 years ago
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