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horrorfan [7]
3 years ago
5

You're studying how well students remember vocabulary after they stop studying a new language. The first student you study remem

bers 95% of the
French words she learned 3 months later, but only 70% of the words 12 months
later.
Before studying more students, you wonder: Is a decreasing linear model or an
exponential decay model likely to be a better fit for data about remembering?
Decide which model you think will be better. Explain your reasoning.
Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

Exponential decay model

Step-by-step explanation:

A quick graph shows the remembrance pattern is not linear because the slope is not the same. Therefore a very likely remembrance pattern will be exponentially related.

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Choose all of the transformations that would change a triangle into one that is similar, but not congruent. Which transformation
Vsevolod [243]

You didn't supply a list.  The so-called rigid transformations of translation, rotation and reflection create congruent triangles.

Generally it's dilation by a factor about a point is preserves similarity but not congruency.  Any transformation which includes such scalings but is otherwise rigid also preserves similarity but not congruency.


8 0
3 years ago
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
11. The student council is comparing prices for their semi-formal dance. They compare banquet. Hall A charges $40 per person. Ha
Natalka [10]

Answer:

TC (A) = 40x , TC (B) = 500 + 20x

Step-by-step explanation:

Let the number of students be = x

Hall A Total Cost

Relationship Equation, where TC (A) = f (students) = f (x)                                40 per person (student) = 40x

Hall B Total Cost

Relationship Equation, where TC (B) = f (students) = f (x)                          500 fix fee & 20 per person (student) = 500 + 20x

4 0
3 years ago
Simplify this expression 4×11×
bonufazy [111]
44 is the answer cause xs cancel out
6 0
3 years ago
Read 2 more answers
Write the equation of the line in point-slope form of the given point and slope. This is an essay style question. If you hit the
svp [43]

Answer:

<h3>y + 2 = 3/7(x-7)</h3>

Step-by-step explanation:

The point-slope form of the equation will be expressed as;

y - y0 = m(x-x0) where;

m is the slope

(x0, y0) is the point on the line

Given

Slope m = 3/7

Point (x0, y0) = (7, -2)

Substitute into the equation;

y - y0 = m(x-x0)

y - (-2) = 3/7 (x - 7)

<em>y + 2 = 3/7(x-7)</em>

<em>Hence the equation in point-slope form is y + 2 = 3/7(x-7)</em>

3 0
3 years ago
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