1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fiesta28 [93]
3 years ago
15

What are the answer for your these questions?

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

<u>a. 11</u>

<u>b. 9</u>

Step-by-step explanation:

<em>A:</em>

2 x 4 = 8

8 + 3 = 11

<em>B:</em>

-2 x -2 = 4

4 + 5 = 9

Hope this helps! Let me know if it was right!

You might be interested in
Louise used this figure to model the expression 20/4
Svet_ta [14]
The arrows should start at zero because then the expression wouldn't be true. She should have made 5 groups if she had started at zero.
3 0
4 years ago
Read 2 more answers
In Littletown, the probability that a baseball team goes to the city playoffs is
adoni [48]
Answer: B: 0.10

hope this helps :,)
8 0
3 years ago
A painter can paint 180 square feet in 1/2 hour. how many feet can he paint in 2 hours
IgorC [24]
Well 1/2 is one quarter of 2 hours. so if he can paint 180 square feet is 1/2 hour multiply it by four to get 2 hours.  so 180 times 4 is 720.
He can paint 720 square feet in 2 hours
7 0
3 years ago
Read 2 more answers
Solve the system of equations using substitution:<br><br> 7y+2x=16 <br> 5y-9=x
7nadin3 [17]
7y+2(5y-9)=16
7y+10y-18=16
17y=34
y=2

5(2)-9=x
10-9=x
x=1
5 0
3 years ago
Prove that the limit x tends to 1 (2x^4-6x^3+x^2+3)÷(x-1)=-8
elixir [45]
First note that if x\neq1, you have

\dfrac{2x^4-6x^3+x^2+3}{x-1}=2x^3-4x^2-3x-3

Now, you're looking for \delta>0 such that for any \varepsilon>0, you have

|x-1|

Note that you can divide through the left side of the \varepsilon inequality by x-1 once more:

\dfrac{2x^3-4x^2-3x+5}{x-1}=2x^3-2x-5\implies 2x^3-4x^2-3x+5=(x-1)(2x^2-2x-5)

So it follows that you need to find an appropriate \delta that will guarantee

|(x-1)(2x^2-2x-5)|=|x-1||2x^2-2-5|

For the moment, let's fix \delta=1. Then by this assumption, we have

|x-1|

From this we get

\implies0
\implies0
\implies0
\implies-5
\implies1

where the upper bound is what we care about. With this assumption, we then get that

|x-1||2x^2-2-5|

which suggests that \delta can be taken to be either the smaller of 1 or \dfrac{\varepsilon}5, or \delta=\min\left\{\dfrac{\varepsilon}5,1\right\}, to guarantee that the function gets arbitrarily close to -8.
5 0
3 years ago
Other questions:
  • Hey! can you please help me posted picture of question
    15·2 answers
  • Integral of (3x-2)/(x-1)^2
    8·1 answer
  • What is the decimal representation of 7/2
    9·2 answers
  • What is the percent of change of: 50 pounds to 35 pounds?<br> Please show how you did it.
    8·2 answers
  • Determine whether the value given below is from a discrete or continuous data set. In an election poll, Josh received 17, 450, 9
    9·1 answer
  • What are the mean and the median?​
    5·1 answer
  • A company has 95,000 shares of stock to sell. A stockbroker decides to buy equal shares of stock for each of her 250 clients .
    8·1 answer
  • What 34 divided by 1,265
    8·2 answers
  • Ryan mows lawns in the summer. He charges $15 for every 12 hour of mowing. This is represented by the equation y=15x , where y i
    13·1 answer
  • If f(x) = x^2/2-13, what is the value of f(6) ?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!