Question

What is the area of △ABC ?

Answer 1

We will use the area formula when we know 2 sides and an included angle.Area = (1/2) * 13 * sine (44.8) * 13Area = (1/2) * 169 * 0.70463Area = 59.541235
Source:http://www.1728.org/triang.htm

Answer 2

Answer:

$59.5\text{ units}^2$

Step-by-step explanation:

We have been an image of triangle ABC. We are asked to find the area of our given triangle.  

We will use trigonometric formula to find area of triangle, when two sides and one included of a triangle is given:

$\text{Area of triangle}=\frac{1}{2}(ab)\times \text{sin}(C)$, where, a and b represents lengths of sides, and C represents included angle.

Upon substituting our given values in above formula, we will get

$\text{Area of triangle ABC}=\frac{1}{2}(13\cdot 13)\times \text{sin}(44.8^{\circ})$

$\text{Area of triangle ABC}=\frac{1}{2}(169)\times 0.704634209964$

$\text{Area of triangle ABC}=84.5\times 0.704634209964$

$\text{Area of triangle ABC}=59.541590741958\approx 59.5$

Therefore, the area of triangle ABC is 59.5 square units.