If ~v = hv1, v2, v3i and ~w = hw1, w2, w3i are vectors and c is a scalar, then
(a) c~v = hcv1, cv2, cv3i
(b) ~v + ~w = hv1 + w1, v2 + w2, v3 + w3i
(c) ~v − ~w = hv1 − w1, v2 − w2, v3 − w3i.
Answer:
9
Step-by-step explanation:
Cross Multiply: 
Simplify: 4x=36
x=9
Answer:
Step-by-step explanation:
2a-7+15-5a
2a-5a-7+15
-3a+8
Answer:
mee
Step-by-step explanation: