Answer:
s = height above ground
s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)
at t = 0
s = 60 (clearly :)
now when does it hit the bleak earth?
That is when s = 0
4.9 t^2 - 20 t -60 = 0
solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)
t = 6.09 or - 2.01
use t = 6.09
now to do the last part there are two obvious ways to get t at the peak
1. look for vertex of parabola
2. look for halfway between t = -2.01 and t = 6.09
I will do it the hard (11) waay by completing the square
4.9 t^2 - 20 t = -(s-60)
t^2 - 4.08 t = -.204 s + 12.2
t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16
(t-2.04)^2 = -.204(s-80.2)
so
top at 80.2 meters at t = 2.04 s
===============
quick check on time
should be average of 6.09 and -2.01
=4.08 /2 = 2.04 check
Answer:
x = 16.6
Step-by-step explanation:
Since we know the measure of an acute angle (31 degrees) of a right angle triangle, and of the side opposite to the angle (10), and we need to find the measure of the adjacent side "x", we use the tangent function:
which rounded to one decimal is
x = 16.6
slope intercept form:
y = mx + b
m = slope
b = y-intercept
the y-intercept is the place on the y-axis (vertical) where the line crosses. In this problem, the line crosses at (0,4), meaning the y-intercept is 4.
y = mx + 4
the slope is technically the rate of change (rise over run) bewteen points.
If you take the distance from point (-1,3) and (0,4) you get a slope of 1/1, or just 1
y = 1x +4
this could also be:
y = x + 4
(because the 1 is invisible but still there)
Answer:
2 x 10 ^ 6
Step-by-step explanation:
