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3 years ago

A recipe requires sugar, flour and cocoa in the ratio 5:4:1

1 answer:

3 0

Let x be the amount of cocoa you use in the recipe.

then 4x is the amount of flour used, and 5x is the amount sugar used.

x+4x+5x= 550g
10x=550g
x=55g

So, you use 55g of cocoa, 220g of flour, and 275g of sugar.

hope this helps! :)

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Find the area of the figure. (Sides meet at right angles.)

Dafna11 [192]

The area is 70in^2 because you find the area of the square without the missing piece then subtract area of missing piece from total

5 0

3 years ago

Find the radius of convergence, then determine the interval of convergence

galben [10]

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.

First aₙ is noted and then aₙ₊₁ is noted.

For ∑ aₙ, aₙ and aₙ₊₁ is noted.

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = β

If β < 1, then the series converges

If β > 1, then the series diverges

If β = 1, then the series inconclusive

Here $a_{k}$ = $\frac{(x+2)^{k}}{\sqrt{k} }$ and $a_{k+1}$ = $\frac{(x+2)^{k+1}}{\sqrt{k+1} }$

Now limit is taken,

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|$

= $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|$

= $\lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|$

= $|{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}$

= $|{x+2 }|$ < 1

- 1 < ${x+2 }$ < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

#SPJ1

5 0

1 year ago

Read 2 more answers

Fill in the blanks to complete the 4 part conclusion. There is suggestive, but inconclusive evidence the Velvetleaf seed beetle

Anarel [89]

Answer:

a) There is suggestive evidence the velvet leaf seed is successful at weed control.

b) Lower bound: 3.699 Upper bound: 6.629

c) Since the confidence interval contains the average percent of seeds to be infected by the beetle (5.164), so we fail to reject the null hypothesis at the specified level of significance.

Step-by-step explanation:

See attached picture.