You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal
all $12$ cards at random to four players, so that each player gets three cards. What is the probability that each player gets an Ace, a $2$, and a $3$?
1 answer:
Answer:
Probability each player gets an ace, a $2 and a $3 = 0.0374
Step-by-step explanation:
The total number of ways to divide the card in triples among four players = 369600 ways
The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways
Probability each player gets an ace, a $2 and a $3 = 13824/369600
Probability each player gets an ace a $2 and a $3 = 0.0374
Note: Further explanation is provided in the attachment.
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After 20 days Chelsea, Jordan and Maddy will be working together !
<u>Step-by-step explanation:</u>
Here we have , Chelsea, Jordan and Maddy all work at the same clothing store. Chelsea works every other day. Jordan works every fourth day and Maddy works every fifth day. Today they all worked together. We need to find How many days will it be until they work together again . Let's find out:
According to given scenario we have , Chelsea works every other day i.e. in 1 day. Jordan works every fourth day i.e. in 4 days and Maddy works every fifth day i.e. in 5 days . In order to find How many days will it be until they work together again we will calculate LCM of all of the three people working days period i.e. 1 , 4 , 5 :
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Since, LCM of all of the three people working days period i.e. 1 , 4 , 5 is 20 , Therefore , After 20 days Chelsea, Jordan and Maddy will be working together !