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3 years ago

Solve for x. 18 ÷ x = -2 x = _____

Mathematics

2 answers:

Otrada [13]3 years ago

7 0

Answer:

-9

Step by step explanation:

it can also be written as; 18 over x is equal to -2 over 1

you cross multiply to get 18 = -2x

then multiply through with -2; 18 over -2 = -2x over -2

you cross out; -2 cancels itself and -2 goes into 18 , -9 times

Therefore; the answer is -9

Eddi Din [679]3 years ago

6 0

Answer:

-9

Step-by-step explanation:

18÷x = -2

18 = -2×x

18 = -2x

-9 = x

x = -9

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Simplify (8x^3-5x-1)-(7x^2+6x-10)

irakobra [83]

Answer:

8x^3-7x^2-11x+9

Step-by-step explanation:

(8x^3-5x-1)-(7x^2+6x-10)

remove unnesasary ( )

8x^3-5x-1 -(7x^2+6x-10)

the distribute

8x^3-5x-1 -7x^2-6x+10

combine like terms

8x^3-11x+9-7x^2

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8x^3-7x^2-11x+9

4 0

3 years ago

If x^(2) = 64 and y^(2)= 121 what is the value of x-y?

GalinKa [24]

Step-by-step explanation:

<em>the value of x is 8</em>

8^(2) = 64

the value of y is 11

11^(2) = 121

x - y

= 8 - 11

= -3

<h3>#CMIIW</h3>

3 0

3 years ago

Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)

AlekseyPX

Answer:

The approximate solution to the system is $(-2.7, 2.1)$ .

Step-by-step explanation:

To solve the system of equations $\begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$ you must:

$\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$

$\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7$

$\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1$