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tigry1 [53]
3 years ago
12

9 is what percent of 6

Mathematics
1 answer:
Zigmanuir [339]3 years ago
7 0
9 is what percent of 6 the answer is 150%
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Add x^3 - 4x^2 + 1 to 3x^2 + x <br> Show Your work!
Sladkaya [172]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \: (x {}^{3}  - 4x {}^{2}  + 1) + (3 {x}^{2}  + x)

\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 1 + 3 {x}^{2}  + x

\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 3x {}^{2}  + x + 1

\qquad \sf  \dashrightarrow \:  {x}^{3}  -  {x}^{2}  + x + 1

6 0
2 years ago
Use the order of operations to simplify this expression <br> |7-8|•4+3(-1)
kkurt [141]
1 is the answer 1111111111
3 0
3 years ago
1/4 = x/12 solve for x
Vedmedyk [2.9K]
Answer: x=3
First you cross multiply
Next you swap sides then divide both sides by 4
6 0
2 years ago
The monthy net gains sales for a new sporting goods store were: $7195, $1484, $3224, $8807, $7185, $1730, $2573, $7071, $5360, S
brilliants [131]

Answer:

$7,185 see below ↓

explanation:

With median, it is about the number that appears the most, and since the closest it gets is between $7,071 and $7,195, we have to pick the number that averages in-between which in this case is <em>7,185.</em>

Below, this ↓ array proves the logic.

<em />\left[\begin{array}{ccc}7195&7185&7071\end{array}\right]

5 0
2 years ago
What is the length of BD?
I am Lyosha [343]

Answer:

10\sqrt{3}

Step-by-step explanation:

<u>Trigonometric Ratios </u>

This problem will be solved by the use of a trigonometric ratio called sine because it relates the opposite side of a given angle with the hypotenuse of the triangle.

Selecting the angle of 60° in triangle ABD:

<em>Sine Ratio </em>

\displaystyle \sin 60^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}

\displaystyle \sin 60^\circ=\frac{BD}{20}

Solving for BD:

\displaystyle BD=20\sin 60^\circ

Since

\sin 60^\circ=\frac{\sqrt{3}}{2}

\displaystyle BD=20\frac{\sqrt{3}}{2}

Simplifying:

\boxed{\displaystyle BD=10\sqrt{3}}

4 0
2 years ago
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