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3 years ago

3 plus 27 divided (4 plus 5) 1/3 plus 2/5

Mathematics

2 answers:

Iteru [2.4K]3 years ago

5 0

Answer:

for q4 it 3 but q5 ibk.. .............

pshichka [43]3 years ago

5 0

Answer:

3 + 27 / (4 + 5) = 6

1/3 + 2/5 = 11/15

Step-by-step explanation:

(4 + 5) = 9

27/9 = 3

3 + 3 = 9

1 x 5 = 5

3 x 5 = 15

5/15

2 x 3 = 6

5 x 3 = 15

6/15

5/15 + 6/15 = 11/15

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A rectangular box is designed to have a square base and an open top. The volume is to be 500in.3 What is the minimum surface are

mr_godi [17]

The minimum surface area that such a box can have is 380 square

<h3>How to determine the minimum surface area such a box can have?</h3>

Represent the base length with x and the bwith h.

So, the volume is

V = x^2h

This gives

x^2h = 500

Make h the subject

h = 500/x^2

The surface area is

S = 2(x^2 + 2xh)

Expand

S = 2x^2 + 4xh

Substitute h = 500/x^2

S = 2x^2 + 4x * 500/x^2

Evaluate

S = 2x^2 + 2000/x

Differentiate

S' = 4x - 2000/x^2

Set the equation to 0

4x - 2000/x^2 = 0

Multiply through by x^2

4x^3 - 2000 = 0

This gives

4x^3= 2000

Divide by 4

x^3 = 500

Take the cube root

x = 7.94

Substitute x = 7.94 in S = 2x^2 + 2000/x

S = 2 * 7.94^2 + 2000/7.94

Evaluate

S = 380

Hence, the minimum surface area that such a box can have is 380 square

Read more about surface area at

brainly.com/question/76387

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5 0

2 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

The volume of a sphere is 4/3pi cm^3<br> what is the diameter of the sphere?

aleksandrvk [35]

The Diameter of sphere is 2cm.

Step-by-step explanation:

Given,

Volume of sphere = $\frac{4}{3}\pi \ cm^3$

Let,

diameter = d

As we know,

Volume of sphere = $\frac{4}{3}\pi \ r^3$

Therefore,

$\frac{4}{3}\pi\ r^3 = \frac{4}{3}\pi \\Multiplying\ both\ sides\ by\ \frac{3}{4\pi }\\\frac{3}{4\pi }*\frac{4}{3}\pi \ r^3 = \frac{4}{3}\pi * \frac{3}{4\pi }\\r^3=1\\(r)^3=(1)^3\\r=1$

We know that,

Diameter = 2r

Diameter = 2*1

Diameter = 2 cm

The Diameter of sphere is 2cm.

Keywords: Volume, Diameter

Learn more about diameters at:

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3 0

3 years ago

A local bakery sells cookies for 5.50 per pound and brownies for 7.50

uysha [10]

Answer:

I may be wrong but i think the answer is D

Step-by-step explanation:

We know that y=10, so if we were to multiply 10 by 7.50, it would be 75, not 63, so A and B wouldn't be correct. and we don't know the value of x, so I think D is the best answer.

6 0

3 years ago

Please help me please

baherus [9]

Answer:

The answer is C

4 0

3 years ago