Answer:
$ 0.000912 / pound
Explanation:
Current spot rate : 100 pound / $ or 0.01 $ / pound
In the next period the $ value of the pound can either increase or decrease by 15%
$ Risk-free rate = 5% and
pound Risk-free rate = 1%
Net Risk- free Rate = 5 - 1
= 4%
Risk-Neutral Probability of price Rise (p) = (0.04 - 0.085) / (1.15 - 0.85)
= 0.653
$ price of pound if price rises = 1.15 x 0.01 =$ 0.0115 / pound
$ price of pound if price falls = 0.85 x 0.01 = $ 0.0085 / pound
Strike price = current spot rate (as option is at the money) = 0.01 $ / pound
Therefore, pay offs one period later
if price is $ 0.0115 / pound, pay off (p₁)= 0.0115 - 0.01
= 0.0015$/ Pound
If price is 0.0085 $ / pound, pay off (p₂) = $0
Hence, Expecyed pay off = p₁ x p + p₂ x (1-p)
= 0.0015 x 0.633 + 0 x ( 1 - 0.633)
= $ 0.00095 / pound
Call price = Present value of Expected pay off at Net Risk-free risk
= 0.00095 exp (0.04)
= $ 0.000912 / pound
Part A:
The number of outcomes that each of them will have to choose anyone at random is calculated below.
n = 3 x 3 = 9
This is because, Al will have 3 choices and similarly, Bill will also have three choices. These outcomes are as written below.
S = (1,1), (1,2), (1,3), (2, 1), (2,2), (2, 3), (3, 1), (3, 2), and (3,3)
Part B: To make the same choice, there will only be three outcomes. These are:
S = (1, 1), (2, 2) and (3, 3)
Part C: If neither of them will vote for 2, there will only be four outcomes. This is because each of them will only have two choices. These are:
S = (1, 1), (1, 3), (3, 1), and (3,3)
Answer: a. Only one policy will pay, the premiums for the other contracts will be returned.
Explanation:
When there are multiple insurance contracts from the same insurer and these contracts have a ''Other Insurance With This Insurer'' provision, it means that in cases where the insured wants to claim, they can choose whichever of the policies they want and that one will pay out but they cannot pick them all.
The premiums paid on the other contracts/s will be returned to the insured because it represents excess coverage.
The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5
<u>Given data :</u>
Mean value of gasoline per hour = 875 gallons
Standard deviation = 55 gallons
<h3>Determine the probability of demand being greater than 1800 gallons over 2 hours </h3>
Demand for gas in 1 hour = X₁
Demand for gas in 2 hours = X₁ + X₂
Therefore ; ( X₁ + X₂) ~ N ( u₁+u₂, sd₁² + sd₂² )
In order to calculate probabilities for normals apply the equation below
Z = ( X- u ) / sd
where : u = 1800, sd = √ ( 55² + 55² ) = 77.78
using the z-table
P( Y > 1800) = P( Z > ( 1800 - 1800 ) / 77.78)
= P( Z>0 ) = 0.5
Hence we can conclude that The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5.
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