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Pie
4 years ago
14

David drove the first 6 hours of his journey at 65 km / hour and the last 3 hours of his journey at 80 km / hour . How far is th

e whole journey in km ?

Physics
1 answer:
inessss [21]4 years ago
8 0

Answer:

630 km.

Explanation:

To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.

Case 1:

Speed 1 (S₁) = 65 km / hour

Time 1 (t₁) = 6 hours

Distance 1 (d₁) =?

Speed = Distance /time

S₁ = d₁ / t₁

65 = d₁ / 6

Cross multiply

d₁ = 65 × 6

d₁ = 390 Km

Case 2:

Speed 2 (S₂) = 80 km / hour

Time 2 (t₂ ) = 3 hours

Distance 2 (d₂) =?

Speed = Distance /time

S₂ = d₂ / t₂

80 = d₂ / 3

Cross multiply

d₂ = 80 × 3

d₂ = 240 Km

Finally, we obtained the total distance travelled by David as follow

Distance 1 (d₁) = 390 Km

Distance 2 (d₂) = 240 Km

Total Distance travelled (dₜ) =?

Total distance = distance 1 + distance 2

dₜ = d₁ + d₂

dₜ = 390 + 240

dₜ = 630 km

Therefore, the total distance travelled by David is 630 km

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Along the western side of the Coast Range the climate is dominated by the Pacific Ocean. Warm winters, cool summers, small daily and seasonal temperature ranges, and high relative humidities are characteristic of this area.

Explanation:

3 0
4 years ago
A 2.0 kg tumor is being irradiated by a radioactive source.The
navik [9.2K]

Answer:

426136363636.36365 Bq

Explanation:

Grays = 12

Mass = 2 kg

Time = 880

Energy = 0.4 MeV

Activity is given by

Activity=\dfrac{Grays\times Mass}{Time\times 0.4}\\\Rightarrow Activity=\dfrac{12\times 2}{880\times 0.4\times 1.6\times 10^{-13}}\\\Rightarrow Activity=426136363636.36365\ Bq

The activity N//t of the radioactive source is 426136363636.36365 Bq

6 0
4 years ago
If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'
Vitek1552 [10]

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge q= 10^{-6}\ C

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

F = \dfrac{kq_{1}q_{2}}{r^2}

Where, q = charge

r = distance

F = force

Put the value into the formula

1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}

r=\sqrt{9\times10^{9}\times(-10^{-6})^2}

r=0.095\ m

r= 9.5\ cm

Hence, The distance between the charges is 9.5 cm

4 0
3 years ago
Two students, standing on skateboards, are initially at rest, when they give each other a shove! After the shove, one student (7
Elden [556K]

Answer:

The other student (59kg) moves right at 7.44 m/s

Explanation:

Given;

mass of the first student, m₁ = 77kg

mass of the second student, m₂ = 59kg

initial velocity of the first student, u₁ = 0

initial velocity of the second student, u₂ = 0

final velocity of the first student, v₁ = 5.7 m/s left

final velocity of the second student, v₂ = ? right

Apply the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(77 x 0) + (59 x 0) = (-77 x 5.7) + (59 x  v₂)

0 = - 438.9 + 59v₂

59v₂ = 438.9

v₂ = 438.9 / 59

v₂ = 7.44 m/s to the right

Therefore, the other student (59kg) moves right at 7.44 m/s

6 0
3 years ago
What is the bond between oxygen and hydrogen in nitric acid
Damm [24]

Answer:

The spectra are consistent with a structure in which the nitric acid forms a near-linear, 1.78 Å hydrogen bond to the oxygen of the water.

Explanation:

Hope this helps you

8 0
3 years ago
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