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Natalka [10]
3 years ago
12

A football game customarily begins with a coin toss to determine who kicks off. The referee tosses the coin up with an initial s

peed of 6.00 m/s. In the absence of air resistance, how high does the coin go above its point of release
Physics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

The coin travels 1.8348 meters above its point of release.

Explanation:

Initial speed = 6 m/s (Assumed vertical speed as not stated in question)

Final Speed = 0 m/s    (at the highest point in air)

Acceleration due to gravity = -9.81 m/s^2

Equation of motion used:

(V_f)^2 - (V_i)^2 = 2 *a * s

0^2 - 6^2 = 2 * (-9.81) * s

s = 1.8348 m

Thus, the coin will travel 1.8348 meters up to its highest point in the air.

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What happens to the position of an object as an unbalanced force acts on?
jarptica [38.1K]

Answer:

Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

5 0
3 years ago
Read 2 more answers
In the Zeeman effect, the energy levels of hydrogen are split by a magnetic field. Each state with a different value of mlml has
Nikolay [14]

Answer:

the Zeeman effect without spin is three lines

Explanation:

The Zeeman effect is the result of the interaction of the magnetic field with the orbital angular momentum of the electrons, if we do not take the spin into account it is called the Normal Zeeman effect.

Therefore we only take into account the orbital moments (m_l) of the transition, from the selection rules of the refreshed harmonics, only the transition with

             \Delta m_l = 0, ± 1

            ΔE \DeltaE = \mu_B \ \Delta  m_l \ B

Let's analyze for the case of the Hydrogen atom

For a transition between levels n = 1 and n = 2 the values ​​of m_l are n_f = 1 m_l = 0 and for n₀ = 2  m_l = 0, 1

so we only have two lines.

For transition n_f = 2 and n₀ = 3

n_f = 2    m_l = 0, 1

n₀ = 3      m_l = -1, 0, 1

There are only two lines plus the central line, so there are three spectral lines

for n_f = 3 and n_o = 4

n_f = 3   ml = -1, 0, 1

n₀= 4      ml = -2, -1, 0, 1, 2

Only transitions with  Δm_l = ±1 are allowed, so there are only two transitions plus the central transition (Δm_l = 0), so there are only 3 spectral lines.

In summary, due to the selection rule of spherical harmonics, the greatest number of lines in the Zeeman effect without spin is three lines.

3 0
3 years ago
A machine with a 5-N input force and a 25-N output force has a mechanical advantage of?
jolli1 [7]
So we want to know the mechanical advantage of a machine that has 5 N input force and 25 N out force. Mechanical advantage Ma is the measure of force amplification of some machine. We calculate it by taking the ratio of the output force Fo over the input force Fi. Ma=Fo/Fi=(25 N)/(5 N)=5. So Mechanical advantage for our machine is Ma=5 and the correct answer is the second one. 
8 0
3 years ago
5. You're examining some of the tiny printing on one of the newer twenty-dollar bills. A 1.5 mm tall letter appears 3 mm tall an
kow [346]

Answer:

80mm or 8cm

Explanation:

According to the lens formula,

1/f = 1/u+1/v

If the object distance u = 4cm = 40mm

Object height = 1.5mm

Image height = 3mm

First, we need to get the image distance (v) using the magnification formula Magnification = image distance/object distance = Image height/object height

v/40=3/1.5

1.5v = 120

v = 120/1.5

v = 80mm

The image distance is 80mm

To get the focal length, we will substitute the image distance and the object distance in the mirror formula to have;

1/f = 1/40+1/-80

Note that the image formed by the lens is an upright image (virtual), therefore the image distance will be negative.

Also the focal length of the converging lens is positive. Our formula will become;

1/f = 1/40-1/80

1/f = 2-1/80

1/f = 1/80

f = 80mm

The focal length of the lens 80mm or 8cm

5 0
4 years ago
Read 2 more answers
The sun is about 150 million km away from earth. The rays of sunlight that reach earth’s atmosphere are best represented as ____
tangare [24]

Five

The diagram that represents rays from the sun is given below.

The answer from the diagram is parallel lines.

Six

The formula for this is n_i * Sin(i) = n_r * sin(r)

n1 = 1.333 water

n2 = 1.309 ice

i (angle) = 40o

r (angle) = ?

Solution

1.333 * sin(40) = 1.309*sin(r)

1.333 * sin(40)/1.309 = sin(r)

0.6546 = sin(r)

sin-1(0.6546)  = 40.88 degrees.

I guess my closest answer would be A. I'm not rounding at all and that's the answer I get.

6 0
3 years ago
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