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sineoko [7]
3 years ago
15

Round 877.71 to the nearest tenth

Mathematics
2 answers:
andrey2020 [161]3 years ago
6 0
877.71 rounded to the nearest tenth is 877.7~
Rainbow [258]3 years ago
4 0
The 7 after the decimal is in the tenths place, so look at the one in the hundredths place. It is less than 5, so the 7 is not rounded up and stays 7. 877.7 is 877.71 rounded to the nearest tenth.
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Subtract: 4x/x^2-25 - 2/x^2+2x-15
Alex777 [14]

Answer: \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

Step-by-step explanation:

Given

Subtract the expression

\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

4 0
3 years ago
A 32 year old mother realized that her age is twice the sum of her two children ages. Her son Jose is two years older than her d
jenyasd209 [6]
Again, guess and test should work perfectly fine.  Since 2(x+y)=32, x+y = 16. Because y-2 =x, y could be = 9 and x = 7. Hope that help!
3 0
3 years ago
Read 2 more answers
Find all pairs of natural numbers which can be the solution to the equation a+b=42.
Setler [38]

Answer:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

Step-by-step explanation:

To find all pairs of natural numbers which are solution to a+b=42, we need to first choose a value to one of them (let's choose 'a'), and that value will be the lowest possible, so we begin with a=1, and then we increase to 2, and 3, and so on.

For each value of a, we calculate the value of b using the equation.

So, starting with a=1, we have that b=41

Then, with a=2, we have that b=40, and so on.

Doing this until a=41 (so b=1 will be the lowest value possible for b), we have the pairs of natural number we want:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

5 0
3 years ago
Please help and explain how
azamat
18, 42, and 27. they were all times by 2
7 0
3 years ago
The roots of a quadratic equation are (1,0) and (-5,0). What is the axis of symmetry?
leva [86]

Answer:

Step-by-step explanation:

The axis of symmetry lies exactly halfway between the given x = 1 and x = -5.

The axis of symmetry is x = -2.

The 'halfway' value is also the 'average' of 1 and -5:  -4/2, or -2.

The axis of symmetry is x = -2.

8 0
3 years ago
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