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Firdavs [7]
2 years ago
5

Disc uses​ activity-based costing. Two of Disc​'s production activities are kitting ​(assembling the raw materials needed for ea

ch computer in one​ kit) and boxing the completed products for shipment to customers. Assume that Disc spends $ 6 comma 000 comma 000 per month on kitting and $ 18 comma 000 comma 000 per month on boxing. Disc allocates the​ following: font size increased by 1 font size increased by 1 Bold font size increased by 1 font size increased by 1 font size increased by 1 times Kitting costs based on the number of parts used in the computer font size increased by 1 font size increased by 1 Bold font size increased by 1 font size increased by 1 font size increased by 1 times Boxing costs based on the cubic feet of space the computer requires Suppose Disc estimates it will use 120 comma 000 comma 000 parts per month and ship products with a total volume of 22 comma 500 comma 000 cubic feet per month. Assume that each desktop computer requires 100 parts and has a volume of 9 cubic feet. The predetermined overhead allocation rate for kitting is ​$0.05 per part and the predetermined overhead allocation rate for boxing is ​$0.80 per cubic foot. What are the kitting and boxing costs assigned to one desktop​ computer? ​(Round all calculations to the nearest​ cent.)
Business
1 answer:
Viktor [21]2 years ago
8 0

<u>Solution and Explanation:</u>

The Overhead allocation rates are to be computed for determining the total cost of producing 1 unit of disc.

Total of 100 parts are used in disc . therfore, the total kitting cost per disc is ( 100 parts multiply with 0.05). Volume of cubic feet is used in one of the disc. therfore, the total boxing cost per disc is ( 9 cubic feet multiply with 0.80)

Total kitting cost per disc = $5.0

Total boxing cost per disc = $7.2

The total kitting cost and boxing cost for one desktop computer are computed by multiplying the allocation rate applicable for per unit of kitting and boxing with the total number of units needed.

Assuming the overhead rate applicable for per unit of kitting and boxing is the total cost incurred for one desktop computer.

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Answer:

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Secure Your Exit

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Fight the Fire

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8 0
2 years ago
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If you wanted to measure a 90-degree bend on a sheet-metal bracket, what instrument would you use?
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8 0
3 years ago
Broward Corp. owns 1,500 shares of Silver Fox Corporation common stock. Broward Corp. purchased the 1,500 shares on April 17,200
Alborosie

Answer:

Disallowed loss = 1428.57

Explanation:

given data

                   Units      total cost

17 Apr, 09           1500   20000

8 Dec, 14             -750   -5000

2 Jan, 15              250    1750

2 Jan, 15                50    1000

solution

we get  here Broward  realized and recognized loss that is

The loss or gain on sale         (5000 - 20000 ÷ 2)    -5000

Allowed loss                          (750 ÷ 1050) × 5000     3571.43

Disallowed loss                                                             1428.57

6 0
3 years ago
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7 0
1 year ago
Suppose 20.0 g pieces of gold and iron, both initially at 100oC, are added to different containers of water, both initially at 2
Sauron [17]

Answer:

  • The final temperature in the container with Gold is 27.49 ⁰C
  • The final temperature in the container with Iron is  33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

Explanation:

Q = mcΔT

Where;

Q is the quantity of heat gained or lost

m is the mass of the metals or water

c is the specific heat capacity

ΔT is the change in temperature, T₂ - T₁

T₂  is the final temperature and T₁ is the initial temperature

Heat lost by metals at 100°C is equal to heat gained by water at 25°C

-Q_{metal} = Q_{water}

-Q_{Au} = Q_{H_2O} \\-Q_{Fe}  = Q_{H_2O}

Specific heat capacity of water = 4.18 J/g°C

Specific heat capacity of gold = 0.129 J/g°C

Specific heat capacity of iron  = 0.45 J/g°C

⇒For Gold

-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)

-2.58T₂ +258 = 75.24T₂  - 1881

77.82T₂  = 2139

T₂  = 2139/77.82

T₂ = 27.49 ⁰C

⇒For Iron

-20*0.450*(T₂ - 100) = 18*4.18 (T₂  - 25)

-9T₂  +900 = 75.24T₂ - 1881

84.24T₂ = 2781

T₂  = 2781/84.24

T₂ = 33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

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3 years ago
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