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stepan [7]
3 years ago
6

Econometrics answers using the ols estimates shown in the table​ below, compare the estimated effects of a 13 ​% increase in ave

rage district income on test scores in california and massachusetts.
Mathematics
1 answer:
Elanso [62]3 years ago
7 0
Please Send Lions, Monkeys, Cats And Zebras Into Lovely Hot Countries
Signed General Penguin
P - potassium
S - sodium
L - lithium
M - magnesium
C - calcium
A - aluminium
Z - zinc
I - iron
L - lead
H - hydrogen
C - copper
S - silver
G - gold
<span>P - platinum</span>
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A triangle has an area of 12 square millimeters. What could be the measures of the base and height of the triangle in millimeter
Taya2010 [7]

A = bh/2

12= bh/2

bh = 24

We need to find pairs that multiply to 24

Answer:    b=3 and h=8 ,  b=6 and h=4, b=12 and h=2​

8 0
3 years ago
A gardener installed 42.6 meters of fencing in a week. He installed 13.45 meters on Monday and 9.5 meters on Tuesday . He instal
kvasek [131]
6.55 meters of fencing. Simply subtract 13.45 meters and 9.5 meters from 42.6 meters, and then divide by 3.

8 0
3 years ago
(No links!) Ill give brainliest and 20+ points to decent answer and this is due today!
Kaylis [27]

Answer:

The answer for number 1 is Bill, his questions is statistical because he is collecting and analyzing data.  But Lisa is just asking what their favorite book was.

Step-by-step explanation:

moreover ) Lisa, because there can be many answers to the question.

2) 4.5 points.

4 0
3 years ago
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
Please help ASAP and explain the answer, thank you
jonny [76]

Answer:

Step-by-step explanation:

1) x² - 8x + 5 = 0

2) No subtract 5 from both sides

x² - 8x + 5 - 5 = 0 - 5

x² - 8x  = -5

3) Now find (8/2) = 4. Add 4² = 16 to both sides

x² - 8x + 16 = -5 + 16

x² - 8x + 16 = 11

4) (x - 4)²  = 11

5) Take square root both sides

x - 4 = ±√11

x = 4 ±√11

6 0
3 years ago
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