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2 years ago

14

Which can be represented using the product (50) × (-5)?

2 answers:

Alina [70]2 years ago

7 0

Answer:

4th option

Step-by-step explanation:

Because the -5 is negative, it has to be something being lost.

Hope this helps! Have a nice day!

andrezito [222]2 years ago

5 0

Answer: D

Explanation: Losing altitude by 5 feet every second, but for 50 seconds, so it is 50 x (-5)

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Translate this sentence into an equation. The product of Mabel's score and 6 is 90 . Use the variable m to represent Mabel's sco

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3 years ago

What statement is conclusive?

WINSTONCH [101]

What statement is conclusive
A: if a b oddthan a b is odd

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3 years ago

Read 2 more answers

What's is the converse of the statement?If x is odd, then 2x is even.

dsp73

If you have two statements p and q and $p\Rightarrow q$ is true, then $\neg q\Rightarrow \neg p$ is also true.

In your case, statements are p - "x is odd" and q - "2x is even".

Then $\neg p$ - "x is not odd" and $\neg q$ - "2x is not even."

Hence $\neg q\Rightarrow \neg p$ sounds as: "If 2x is not even, then x is not odd".
Answer: correct choice is D.

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3 years ago

Jeanne has $12.50 in her bag. How much money does she need to buy a game that costs $72.60?

ololo11 [35]

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Step-by-step explanation:

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4 0

3 years ago

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago