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aev [14]
3 years ago
6

Very short pulses of high-intensity laser beams are used to repairdetached portions of the retina of the eye. The brief pulses o

fenergy absorbed by the retina welds the detached portion back intoplace. In one such procedure, a laser beam has a wavelength of 900nm, and delivers 258 mW, of power spread over a circular spot 595{\mu}m, in diameter. The vitreous humor (the transparent fluid thatfills most of the eye) has an index of refraction of 1.34.Part A If the laser pulses are each 1.5 ms, long, how much energy isdelivered to the retina with each pulse?Part B What average pressure does the pulse of the laser beam exert on theretina as it is fully absorbed by the circular spot?Part C What is the wavelength of the laser light inside the vitreous humorof the eye?Part D What is the frequency of the laser light inside the vitreous humorof the eye?Part E What is the maximum value of the electric field in the laserbeam?Part F What is the maximum value of the magnetic field in the laserbeam?
Physics
1 answer:
maw [93]3 years ago
7 0

Answer:

a)  W = 3.87 10⁻⁴ J , b)  P = 3.10 10⁻³ Pa , c)  λ = 671. 6 nm , d) frequency does not change , e)  Emax = 1.39 C / m  and f) Bmax = 4.7 10⁻⁹ T

Explanation:

a) Let's use the concepts of power that is work for the unit of time and work is the change of kinetic energy

    P = W / t

An electromagnetic wave has an intensity

    I = P / A =

   W = P t

   W = 258 10⁻³ 1.5 10⁻³

   W = 3.87 10⁻⁴ W s

   W = 3.87 10⁻⁴ J

b) the radiation pressure is given by the ratio

    P = I / c

Where I is the intensity

     I = Powers / A

    A = π r² = π (d/2)²

     I = 258 10⁻³ / π (297.5 10⁻⁶)²

     I = 9.29 10 5 W / m²

     P = 9.29 10⁵/3 10⁸

     P = 3.10 10⁻³ Pa

c) The wavelength when passing a measured of different refractive index changes in the way

     λ = λ₀ / n

     λ = 900 10⁻⁹ / 1.34

     λ = 671.6 10⁻⁹ m

     λ = 671. 6 nm

d) when the light strikes a medium creates a forced oscillation in the electrons of the medium, this is a resonance phenomenon, so the frequency does not change

e) The maximum electric field is

      I = Emax2 / 2 μ₀ c

     Emax = Ra (2 μ₀ c I)

     Emax = Ra (2 4 π 10⁻⁷ 3 10⁸ 258 10⁻³)

     Emax = 1.39 C / m

f) the elective and magnetic fields are related

     c = Emax Bmax

     Bmax = Emax / c

     Bmax = 1.39 / 3 10⁸

     Bmax = 4.7 10⁻⁹ T

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