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2 years ago

Select all the correct answers.

Biology

1 answer:

nexus9112 [7]2 years ago

6 0

Answer:

The correct answer is : As we gain mass, the force of gravity on us increases.

Explanation:

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Answer:j

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3 years ago

Passive transport does not use ATP andfollows a concentration gradient<br> False or <br> True

inysia [295]

Answer:

True

Explanation:

Since it's a passive way of transport, it is in favor of the concentration gradient and does not need to use ATP.

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The mass extinction occurring today differs from those that occurred in the past because

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2 years ago

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Circle the letter of each example of mechanical weathering.

Elan Coil [88]

$\huge{Heya!}$

<h3>The answer to this will be is : </h3><h2 /><h2>C. Plant roots grow into a crack in a rock.</h2><h2 /><h2> $\textbf{EXPLANATION :}$ </h2><h2 />

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Because "mechanical weathering" It's a example of the Plants roots that grow on into a crack in the rock.

Hope It Helped!

<u>And Tell me if The answer is wrong. . .</u>

<h2><u>Good Luck With Your Assignment!</u></h2><h2 />

#LearnWithBrainly

$\text{\underline{ANSWER :}}$

$\textbf{Jace}$ ﾉｼ

5 0

2 years ago

Examine the genotype for an individual who is AaBbCcDc. Predict the outcomes of meiosis and the potential gamete combinations th

Katarina [22]

Answer: 16 different gametes

ABCD
ABCd
ABcD
ABcd
AbCD
AbCd
AbcD
Abcd
aBCD
aBCd
aBcD
aBcd
abCD
abCd
abcD
abcd

Explanation:

Gamete formation involves the random and independent segregation of alleles. During anaphase 1 (meiosis), occurs the independent separation of homologous chromosomes that migrate to opposite poles of the cell. This separation generates different chromosomal combinations in the daughter cells. There are two alternatives per homologous pair.

The number of gametes with different combinations is 2ⁿ, where

n = number of homologous pairs.

In the exposed example there are 4 pairs of chromosomes, so

the number of possible combinations of chromosomes = 2ⁿ = 2⁴ = 16

Individual: AaBbCcDdEe

You can make use of the fork line method to easily figure out the possible gametes.

A.......B.........C........D → ABCD

........d → ABCd

...........c.........D → ABcD

........d → ABcd

b.........C........D → AbCD

........d → AbCd

...........c.........D → AbcD

........d → Abcd

a.......B.........C........D → aBCD

........d → aBCd

...........c.........D → aBcD

........d → aBcd

b.........C........D → abCD

........d → abCd

...........c.........D → abcD

........d → abcd

7 0

2 years ago